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2 years ago

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An airplane was cruising at 23,000 feet altitude. Due to turbulence it dropped 4,300 feet.Once the air currents leveled off he w

ent back up 3,600 feet. How far was he from his original cruising altitude?

1 answer:

vladimir1956 [14]2 years ago

4 0

Answer:

-700 feet, aka 700 feet below/away from the original cruising altitude

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Please answer in a little bit detail

xeze [42]

Answer:

what the heck i think pre-alegbra is hard what do they expect from us ? the mother freaking world ? like no

Step-by-step explanation:

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2 years ago

Questions attached as screenshot below:Please help me I need good explanations before final testI pay attention

Nikitich [7]

The acceleration of the particle is given by the formula mentioned below:

$a=\frac{d^2s}{dt^2}$

Differentiate the position vector with respect to t.

$\begin{gathered} \frac{ds(t)}{dt}=\frac{d}{dt}\sqrt[]{\mleft(t^3+1\mright)} \\ =-\frac{1}{2}(t^3+1)^{-\frac{1}{2}}\times3t^2 \\ =\frac{3}{2}\frac{t^2}{\sqrt{(t^3+1)}} \end{gathered}$

Differentiate both sides of the obtained equation with respect to t.

$\begin{gathered} \frac{d^2s(t)}{dx^2}=\frac{3}{2}(\frac{2t}{\sqrt[]{(t^3+1)}}+t^2(-\frac{3}{2})\times\frac{1}{(t^3+1)^{\frac{3}{2}}}) \\ =\frac{3t}{\sqrt[]{(t^3+1)}}-\frac{9}{4}\frac{t^2}{(t^3+1)^{\frac{3}{2}}} \end{gathered}$

Substitute t=2 in the above equation to obtain the acceleration of the particle at 2 seconds.

$\begin{gathered} a(t=1)=\frac{3}{\sqrt[]{2}}-\frac{9}{4\times2^{\frac{3}{2}}} \\ =1.32ft/sec^2 \end{gathered}$

The initial position is obtained at t=0. Substitute t=0 in the given position function.

$\begin{gathered} s(0)=-23\times0+65 \\ =65 \end{gathered}$

8 0

10 months ago

suppose Q is the midpoint of PR. use the information to find the missing value. PQ equals 3x + 14 and QR equals 7X - 10; find X.

NARA [144]

Answer:

x=6

Step-by-step explanation:

A midpoint is the middle point of a line segment, therefore it is equal distances from both ends of the segment.

This means that PQ and QR have the same length. So all we have to do is set each value equal to each other, and then solve for X.

$3x+14=7x-10\\3x+24=7x\\24-4x\\x=6$

4 0

2 years ago

Read 2 more answers

Three integers between -4 and 0

balu736 [363]

Integers between -4 and 0 are : -3, -2, and -1

7 0

2 years ago

Read 2 more answers

Neelam's daily income is ₹ 800. Her daily savings amount is ₹100. What is the ratio of her SAVINGS to her EXPENDITURE?

sveta [45]

Answer: ratio of her SAVINGS to her EXPENDITURE=1:7

Step-by-step explanation:

Neelam's daily income = ₹ 800

Neelam's daily savings amount = ₹100

Therefore her expenditure will be Daily income - Daily savings

= ₹ 800- ₹ 100= ₹ 700

ratio of her SAVINGS to her EXPENDITURE

= 100: 700

=1:7

3 0

2 years ago