Quadrilateral RICE is a rectangle because the lengths of the quadrilateral have 2 sides congruent to each other. Also, RICE has slopes with opposite fractions which make the sides parallel to each other.
52.5 Yards (yd).
7 + 7 = 14
14 + 14 = 28 ( 10 + 10 + 4 + 4)
14 + 28 = 42 (4 - 2 + 8 = 10 + 20 + 10)
42 + 10.5 = 52.5
⚠⚠ if you need to multiply this by itself (squaring is the proper name) then the answer is 2756.25 Yards.
The question is incomplete :
The height, width and Lenght isn't Given. However, we can create an hypothetical scenario, with a height 6, length 8 and width 4
Answer:
192 unit³
Step-by-step explanation:
The volume of the card box :
Recall the volume of box formula :
V = length * width * height
Volume = 8 * 6 * 4
Volume = 192 unit³
This is the procedure for any given dimension of the card deck.
Answer:
7.280 k
Step-by-step explanation:
Given that 1 g = 0.001 k
If he uses 520 grams of flour each day for 2 weeks, since there are 7 days in a week, the total weight of flour used in two weeks
= 520 g * 2 * 7
= 7280 g
In kilograms
Since
1 g = 0.001 k
7280 g = 7280/1 * 0.001 k
= 7.280 k
<span>12.3
Volume function: v(x) = ((18-x)(x-1)^2)/(4pi)
Since the perimeter of the piece of sheet metal is 36, the height of the tube created will be 36/2 - x = 18-x.
The volume of the tube will be the area of the cross section multiplied by the height. The area of the cross section will be pi r^2 and r will be (x-1)/(2pi). So the volume of the tube is
v(x) = (18-x)pi((x-1)/(2pi))^2
v(x) = (18-x)pi((x-1)^2/(4pi^2))
v(x) = ((18-x)(x-1)^2)/(4pi)
The maximum volume will happen when the value of the first derivative is zero. So calculate the first derivative:
v'(x) = (x-1)(3x - 37) / (4pi)
Convert to quadratic equation.
(3x^2 - 40x + 37)/(4pi) = 0
3/(4pi)x^2 - (10/pi)x + 37/(4pi) = 0
Now calculate the roots using the quadratic formula with a = 3/(4pi), b = -10/pi, and c = 37/(4pi)
The roots occur at x = 1 and x = 12 1/3. There are the points where the slope of the volume equation is zero. The root of 1 happens just as the volume of the tube is 0. So the root of 12 1/3 is the value you want where the volume of the tube is maximized. So the answer to the nearest tenth is 12.3</span>
