The net force on particle particle q1 is 13.06 N towards the left.
<h3>
Force on q1 due to q2</h3>
F(12) = kq₁q₂/r₂
F(12) = (9 x 10⁹ x 13 x 10⁻⁶ x 7.7 x 10⁻⁶)/(0.25²)
F(12) = -14.41 N (towards left)
<h3>Force
on q1 due to q3</h3>
F(13) = (9 x 10⁹ x 7.7 x 10⁻⁶ x 5.9 x 10⁻⁶)/(0.55²)
F(13) = 1.352 N (towards right)
<h3>Net force on q1</h3>
F(net) = 1.352 N - 14.41 N
F(net) = -13.06 N
Thus, the net force on particle particle q1 is 13.06 N towards the left.
Learn more about force here: brainly.com/question/12970081
#SPJ1
As we know,
so, let's solve for charge (q) :
time = 5 minutes = 5 × 60 seconds = 300 seconds.
hence, the charge = 60 coulombs (C)
Answer:
2 m/s
Explanation:
= Mass of red truck = 1000 kg
= Mass of green truck= 3000 kg
= Initial Velocity of red truck = 6 m/s
= Initial Velocity of green truck
= Velocity with which they move together = 0
For elastic collision
Velocity of the green truck is 2 m/s
Heat makes things expand, so in hot water the ballon will get bigger
If the transformer’s primary coil has 20 times as many turns of wire in it as the secondary coil has, then the secondary coil provides a small voltage rise for the large amount of current that flows through it.
Answer: Option B
<u>Explanation:</u>
A transformer has a two types of coils, the first one is primary coils and the second one is secondary coil. A secondary coils with hardly any turns in it provides the charges going through it just limited quantities of energy.
Without a long separation over which to do chip away at the charges streaming in the loop, the transformer delivers just a little ascent in the voltage of those charges. Be that as it may, the coil can give this little voltage to ascend to a huge current without requiring an excess of power supply from the input circuit.