C. Complete the following combustion reaction. Write your balanced equation two different ways.
1 answer:
<h3><u>Required </u><u>Answer</u><u>:</u></h3>
The substance in reactants side shows a alkane which is burnt. As a result of combustion, Carbon dioxide and water is formed.
The equation will be like this:
Now here we can see that the stoichiometric coefficient is a fraction, hence Multiplying 2 in both sides of the eq.
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Answer:
Explanation:
If we look at the structure of 1-Bromopropane; we will see that it is a derivative of alkane family by the the substitution of an alkyl group. The position of the Bromine in the propane is 1, making 1-Bromopropane a primary alkyl-halide.
Primary alkyl - halide undergo SN2 mechanism. This nucleophilic reaction needs to be a strong alkyl halide , such as 1-Bromopropane used otherwise it will result to a reactive mechanism if a weak electrophile is used.
However, the critical and the main objective here is to Draw the major substitution product if the reaction proceeds in good yield. If no reaction is expected or yields will be poor, draw the starting material in the box. If a charged product is formed, be sure to draw the counterion.
The attached diagrams portraying this notions is shown in the attached file below.
