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anyanavicka [17]

2 years ago

8

the cost of renting a van is $30. An additional $0.89 is charged for each mile, m, the van is driven, Which expression can be us

ed to determine the total cost, in dollars, of renting a van?

1 answer:

kolbaska11 [484]2 years ago

5 0

Answer:

30 + 0.89m

Step-by-step explanation:

I think this is the correct answer.

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Round to the nearest thousand. 5,568

cricket20 [7]

Answer:

Round to the nearest thousand.

5,568

= 5,000

7 0

2 years ago

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$1876 per month for 12 months<br> A) $22,512<br> B) $225.12<br> c) $1888<br> D) None of these

insens350 [35]

Answer:

The answer is A

Step-by-step explanation:

We need to multiply 1876 by 12. 1876 * 12 = 22, 512. That's our answer

5 0

2 years ago

Can someone help me I really need it

Dennis_Churaev [7]

Answer:

The 3 lines are parallel.

Step-by-step explanation:

To draw the lines with the slope of 1/3 choose any point and mark it, then go up 1 square and right 3 squares and mark that point. Draw a line connecting those 2 points. Now choose another point and do the same thing. Then once more. Lines with the same slope are parallel.

Hope this helped! Please mark Brainliest.

8 0

2 years ago

If -y-2x^3=Y^2 then find D^2y/dx^2 at the point (-1,-2) in simplest form

algol13

Answer:

$\frac{d^2y}{dx^2} = \frac{-4}{3}$

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

<u>Algebra I</u>

Factoring

<u>Calculus</u>

Implicit Differentiation

The derivative of a constant is equal to 0

Basic Power Rule:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Product Rule: $\frac{d}{dx} [f(x)g(x)]=f'(x)g(x) + g'(x)f(x)$

Chain Rule: $\frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)$

Quotient Rule: $\frac{d}{dx} [\frac{f(x)}{g(x)} ]=\frac{g(x)f'(x)-g'(x)f(x)}{g^2(x)}$

Step-by-step explanation:

<u>Step 1: Define</u>

-y - 2x³ = y²

Rate of change of tangent line at point (-1, -2)

<u>Step 2: Differentiate Pt. 1</u>

<em>Find 1st Derivative</em>

Implicit Differentiation [Basic Power Rule]: $-y'-6x^2=2yy'$
[Algebra] Isolate <em>y'</em> terms: $-6x^2=2yy'+y'$
[Algebra] Factor <em>y'</em>: $-6x^2=y'(2y+1)$
[Algebra] Isolate <em>y'</em>: $\frac{-6x^2}{(2y+1)}=y'$
[Algebra] Rewrite: $y' = \frac{-6x^2}{(2y+1)}$

<u>Step 3: Differentiate Pt. 2</u>

<em>Find 2nd Derivative</em>

Differentiate [Quotient Rule/Basic Power Rule]: $y'' = \frac{-12x(2y+1)+6x^2(2y')}{(2y+1)^2}$
[Derivative] Simplify: $y'' = \frac{-24xy-12x+12x^2y'}{(2y+1)^2}$
[Derivative] Back-Substitute <em>y'</em>: $y'' = \frac{-24xy-12x+12x^2(\frac{-6x^2}{2y+1} )}{(2y+1)^2}$
[Derivative] Simplify: $y'' = \frac{-24xy-12x-\frac{72x^4}{2y+1} }{(2y+1)^2}$

<u>Step 4: Find Slope at Given Point</u>

[Algebra] Substitute in <em>x</em> and <em>y</em>: $y''(-1,-2) = \frac{-24(-1)(-2)-12(-1)-\frac{72(-1)^4}{2(-2)+1} }{(2(-2)+1)^2}$
[Pre-Algebra] Exponents: $y''(-1,-2) = \frac{-24(-1)(-2)-12(-1)-\frac{72(1)}{2(-2)+1} }{(2(-2)+1)^2}$
[Pre-Algebra] Multiply: $y''(-1,-2) = \frac{-48+12-\frac{72}{-4+1} }{(-4+1)^2}$
[Pre-Algebra] Add: $y''(-1,-2) = \frac{-36-\frac{72}{-3} }{(-3)^2}$
[Pre-Algebra] Exponents: $y''(-1,-2) = \frac{-36-\frac{72}{-3} }{9}$
[Pre-Algebra] Divide: $y''(-1,-2) = \frac{-36+24 }{9}$
[Pre-Algebra] Add: $y''(-1,-2) = \frac{-12}{9}$
[Pre-Algebra] Simplify: $y''(-1,-2) = \frac{-4}{3}$

6 0

2 years ago

If 10 hours makes 120$ then how much money is maken in 1 hour

svetoff [14.1K]

12 i’m pretty sure!!!!

4 0

2 years ago

Read 2 more answers