The least common multiple would be 240.
120(2)=240 AND
80(3)=240
I think the answer to this question is 18
Answer:
Is not possible to compute the angle under those conditions.
Step-by-step explanation:
You need more information, I will be more specific, there is a book called "Geometry" by Moise Downs where the following theorem is stated on the chapter 7.
Let ΔABC and ΔDEF be two triangles where AB = DE and AC = DF if
∠A > ∠D then BC > EF, which in simple terms means that, if two sides are equal, the angle between them can vary as much as you want and that will directly imply the size of the third size of your triangle.
Therefore, there is information missing in order to solve the question
These are congruent angles. So they would be equal to each other. 6x=4x+50
2x=50
x=25°
:)
Answer:
Step-by-step explanation:
No it isn't, because:
![{1.08}^{ \frac{1}{5} } = { \frac{108}{100} }^{ \frac{1}{5} } = { \frac{27}{25} }^{ \frac{1}{5} } = \sqrt[5]{ \frac{27}{25} } = 1.01551](https://tex.z-dn.net/?f=%20%7B1.08%7D%5E%7B%20%5Cfrac%7B1%7D%7B5%7D%20%7D%20%20%3D%20%20%7B%20%5Cfrac%7B108%7D%7B100%7D%20%7D%5E%7B%20%5Cfrac%7B1%7D%7B5%7D%20%7D%20%20%3D%20%20%7B%20%5Cfrac%7B27%7D%7B25%7D%20%7D%5E%7B%20%5Cfrac%7B1%7D%7B5%7D%20%7D%20%20%3D%20%20%5Csqrt%5B5%5D%7B%20%5Cfrac%7B27%7D%7B25%7D%20%7D%20%20%3D%201.01551)
