Your answer would be A because $4800 is your starting number and it increases 2% every year. How much is it in 20 years?
You use the formula ab^x
a is your starting number
b is the percentage
x is always the length of time
Since you are increasing and trying to get its worth larger than what it was before you use a number larger than one hundred percent in this case the number would be 1.02.
Y=4800(1.02)^20
Y=$7132.55
The first (and most typical) way to find distance of two points is by using the distance formula.
One alternative is the Manhattan metric, also called the taxicab metric. This option is much more complicated, and rarely used in high school math. d(x,y)=∑i|xi-yi|
The answer is 22.8
Cos 64 = adj./hypotenuse
Cos64=10/x
X(cos64)=10
X= 10/cos64
= 22.8
Tan²( θ ) - (1 + √3) tan (θ) + √3 = 0
tan²( θ ) - (tan (θ) + √3 tan (θ)) + √3 = 0
tan²( θ ) - tan (θ) - √3 tan (θ) + √3 = 0
tan( θ ) ( tan (θ) - 1) - √3 ( tan (θ) - 1 ) = 0
( tan( θ ) - 1 ) ( tan( θ ) - √3 ) = 0
tan( θ ) - 1 = 0
θ = π/₄
tan( θ ) - √3 = 0
θ = π/₃
so θ = π/₄ and θ = π/₃
Answer:
(x, y) = (1, 3)
Step-by-step explanation:
given the 2 equations
x + y = 4 → (1)
y = 3x → (2)
Substitute y = 3x into (1)
x + 3x = 4
4x = 4 ( divide both sides by 4 )
x = 1
Substitute x = 1 into (2) for corresponding value of y
y = 3 × 1 = 3
solution is (1, 3 )
