Answer:
a) 1.73*10^5 J
b) 3645 N
Explanation:
106 km/h = 106 * 1000/3600 = 29.4 m/s
If KE = PE, then
mgh = 1/2mv²
gh = 1/2v²
h = v²/2g
h = 29.4² / 2 * 9.81
h = 864.36 / 19.62
h = 44.06 m
Loss of energy = mgΔh
E = 780 * 9.81 * (44.06 - 21.5)
E = 7651.8 * 22.56
E = 172624.6 J
Thus, the amount if energy lost is 1.73*10^5 J
Work done = Force * distance
Force = work done / distance
Force = 172624.6 / (21.5/sin27°)
Force = 172624.6 / 47.36
Force = 3645 N
Answer:
Rate = vmax k3/k2+k3
Explanation:
The rate of reaction when the enzyme is saturated with substrate is the maximum rate of reaction, is referred to as Vmax.
This is usually expressed as the Km ie. Michaelis constant of the enzyme, an inverse measure of affinity. For practical purposes, Km is the concentration of substrate which permits the enzyme to achieve half Vmax.
Please kindly check attachment for the step by step solution of the given problem.
Explanation:
The given data is as follows.
Voltage = 2.50 V
Hence, calculate the equivalence capacitor as follows.
=
C =
Now, we will calculate the charge across each capacitance as follows.
Q = CV
=
=
=
Thus, we can conclude that is the charge stored on each given capacitor.
Answer:
c
Explanation:
because I've had this question before and got it right
Answer:
The maximum speed of the mass is 1.67 m/s.
Explanation:
We have,
Mass of object is 34 g or 0.034 kg
Spring constant of the spring is 78.1 N/m
Amplitude attained by the object is 3.5 cm or 0.035 m
It is required to find the maximum speed of the object in this spring mass system. The maximum speed is given by :
Plugging all the values in above formula,
So, the maximum speed of the mass is 1.67 m/s.