<h2>
Answer:<em>
</em><em><u>
w =(-40-√4320)/-34=(20+6√ 30 )/17= 3.110
</u></em></h2><h2><em><u>
w =(-40+√4320)/-34=(20-6√ 30 )/17= -0.757</u></em></h2>
Step-by-step explanation: The prime factorization of 4320 is
2•2•2•2•2•3•3•3•5
To be able to remove something from under the radical, there have to be 2 instances of it (because we are taking a square i.e. second root).
√ 4320 = √ 2•2•2•2•2•3•3•3•5 =2•2•3•√ 30 =
± 12 • √ 30
√ 30 , rounded to 4 decimal digits, is 5.4772
So now we are looking at:
w = ( -40 ± 12 • 5.477 ) / -34
Two real solutions:
w =(-40+√4320)/-34=(20-6√ 30 )/17= -0.757
or:
w =(-40-√4320)/-34=(20+6√ 30 )/17= 3.110
MY HEAD HURTS!
Hey there!
No numbers go into a prime number other than one and that number. 9 and 7 go into 63, so it’s not 63. 3 and 17 go into 51, so it’s not 51. 19 and 3 go into 57, so it’s not 57. That leaves 61. Nothing goes into this other than one and 61, so the answer is 61.
I hope this helps!
n - 7 = 9
Step-by-step explanation:
so basically just make up a random variable and place it for the "twice a number" then u sovle it as a 2 step equation
Answer:
The estimation for the proportion of tenth graders reading at or below the eighth grade level is given by:
And the 90% confidence interval would be given (0.131;0.169).
Step-by-step explanation:
We have the following info given:
represent the sampel size slected
number of students who read above the eighth grade level
The estimation for the proportion of tenth graders reading at or below the eighth grade level is given by:
The confidence interval for the proportion would be given by this formula
For the 90% confidence interval the significance is 
and 
, with that value we can find the quantile required for the interval in the normal standard distribution and we got.
And replacing into the confidence interval formula we got:
And the 90% confidence interval would be given (0.131;0.169).
Answer: 17. is A and 18 is most likely G
Step-by-step explanation:
