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1 year ago

14

Make a claim about how the sun’s energy affects the climate of an area. Provide evidence with factors supporting your claim. Exp

lain your reasoning.

1 answer:

Black_prince [1.1K]1 year ago

4 0

Explanation:

i.d.k sorry

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212 pb 82 is the isotope notation for iron. what is the atomic number, mass number, and number of both protons and neutrons?

o-na [289]

Hello!

The mass number in isotope notation is denoted A, the atomic number is denoted as Z, and the element is denoted as X.

In the given isotope, the mass of the isotope is 212 amu, and the atomic number is 82.

We know that the number of electrons, and protons are equal to the atomic number. Therefore, there are 82 protons. Also, to find the number of neutrons, we subtract the atomic number from the atomic mass.

212 - 82 = 130 neutrons

<u>Final answers</u>:

Atomic Number: 82
Mass number: 212
Number of Protons: 82
Number of Neutrons: 130

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2 years ago

A bobsled has a momentum of 4000 0 kg* m/s to the south. Friction on the track reduces its momentum to 500 kg* m/s to the south.

faltersainse [42]

The correct answer is c

6 0

2 years ago

Read 2 more answers

What is the measured component of the orbital magnetic dipole moment of an electron with (a) ml = and (b) ml = ?

faust18 [17]

ANSWER:

What is the measured component of the orbital magnetic dipole moment of an electron with the values

(a) ml=3

(b ) ml= −4

a) -278 x $10^{-23}$ J/T

b) 3.71 x $10^{-23}$ J/T

STEP-BY-STEP EXPLANATION:

a) ml= 3

Цorb,z = ml Цв = - (3) * (9.27e - 24) = -278 x $10^{-23}$ J/T

b) ml= 3

Цorb,z = ml Цв = - (-4) * (9.27e - 24) = 3.71 x $10^{-23}$ J/T

3 0

2 years ago

Help me plsssssssss Brainliest to correct answer

Elina [12.6K]

It may be unreliable because it might mess something up from the speed.

8 0

2 years ago

The reaction A(B) = 2B(g) has an equilibrium constant of K = 0.045. What is the equilibrium constant for the reaction B(g) =1/2A

Mamont248 [21]

Answer:

The $K_c$ for the reaction $B(g) = \frac{1}{2}A$ will be 4.69.

Explanation:

The given equation is A(B) = 2B(g)

to evaluate equilibrium constant for $B(g) = \frac{1}{2}A$

$K_c=[B]^2[A]$

= 0.045

The reverse will be $2B\leftrightharpoons A$

Then, $K_c = \frac{[A]}{[B]^2}$

= $\frac{1}{0.045}$

= $22m^{-1}$

The equilibrium constant for $B(g) = \frac{1}{2}A$ will be

$K_c = \sqrt{K_c}$

$=\sqrt{22}$

= 4.69

Therefore, $K_c$ for the reaction $B(g) = \frac{1}{2}A$ will be 4.69.

5 0

2 years ago