15+3x-4+6x= 9x+11 add 6+3 then subtract 15-4
3y-4x+8x-y= 4x+2y add -4+8 then subtract 3-1
5x+8x+10x-3x= 20x Add 10+5+8 to get 23 then subtract 3
Answer:
y = -5/4x - 7
Step-by-step explanation:
First, find the slope:
3 - -7 / -8 - 0 = -5/4
Put it in point slope form:
y + 7 = -5/4(x-0)
y + 7 = -5/4x
y = -5/4x - 7
Answer:
s=15
r=10
Step-by-step explanation:
What we know)
The measure of a line is 180º
If two parrel lines are cut by a transversal, the corresponding angles are congruent (corresponding angles postulate)
What we can figure out)
The angle measuring 3r+3s and 6r+3s are on the same line, so
3r+3s+6r+3s=180
3r+3s and 6r+s are corresponding, so
3r+3s=6r+s
Solve)
Now, we just need to solve the equations.
3r+3s+6r+3s=180 can be condensed into 9r+6s=180 by combining like terms. Then, you can divide by 3 to get 3r+2s=60
3r+3s=6r+s can be turned into 2s=3r by subtracting 3r and s.
So we have 3r+2s=60 and 2s=3r
We can substitute 2s for 3r
2s+2s=60
4s=60
s=15
Then, we can plug s=15 into the equation
2(15)=3r
30=3r
r=10
The solution of a system of equations is the point at which the two lines intersect. Since y is already isolated, we can set the equations equal to each other by doing:
4x=4x+1
Subtract 4x from both sides
0=1
Since 0 cannot equal 1 in any case, the lines never intersect. There is no solution to the problem.
Okay so let’s start with number one you have 2 out of the 3 sides and you have to solve for the third
Let’s call the side you are looking for side A than the side with 13 side B and the side with 29 side C
So
B=13
C=29
A= ?
You would use the equation
A^2 + B^2 = C^2
So
A^2 + (13)^2 = (29)^2
13^2 = 169
29^2 = 841
So
A^2 + 169 = 841
A^2 = 672
A= 4 times the square root of 42
Or if yu need a estimated answer
A= 25.9
