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2 years ago

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PLEASE HELP PLEASE HELP PLEASE HELP PLEASE HELP PLEASE HELP PLEASE HELP PLEASE HELP PLEASE HELP PLEASE HELP PLEASE HELP PLEASE H

ELP PLEASE HELP
CHEMISTRY MOLE CONVERSIONSS!!! DUE IN 15 MINS PLEASE HELP ANYBODY!! PLZ DONT ANSWER IF U DONT KNOW!

1 answer:

vfiekz [6]2 years ago

6 0

Answer:

AU9NJ-BLVHV-TCLJS-54YTB

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If 3.00 g of titanium metal is reacted with 6.00 g of chlorine gas, Cl2, to form 7.7 g of titanium (IV) chloride in a combinatio

Crank

Ti + 2 Cl2 → TiCl4

(3.00 g Ti) / (47.867 g Ti/mol) = 0.062674 mol Ti

(6.00 g Cl2) / (70.9064 g Cl2/mol) = 0.084619 mol Cl2

0.084619 mole of Cl2 would react completely with 0.084619 x (1/2) = 0.0423095 mole of Ti, but there is more Ti present than that, so Ti is in excess and Cl2 is the limiting reactant.

(0.084619 mol Cl2) x (1 mol TiCl4 / 2 mol Cl2) x (189.679 g TiCl4/mol) = 8.025 g TiCl4 in theory

(7.7 g) / (8.025 g) = 0.96 = 96% yield TiCl4

6 0

2 years ago

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Of the following equilibria, only ________ will shift to the right in response to a decrease in volume. N2 (g) + 3H2 (g) 2NH3 (g

igomit [66]

Answer:

Of the following equilibria, only one will shift to the right in response to a decrease in volume.

$N_2 (g) + 3H_2 (g)\rightleftharpoons 2NH_3 (g)$

On decreasing the volume the equilibrium will shift in right direction due to less number of gaseous moles on product side.

Explanation:

Any change in the equilibrium is studied on the basis of Le-Chatelier's principle.

This principle states that if there is any change in the variables of the reaction, the equilibrium will shift in the direction to minimize the effect.

Decrease the volume

If the volume of the container is decreased , the pressure will increase according to Boyle's Law. Now, according to the Le-Chatlier's principle, the equilibrium will shift in the direction where decrease in pressure is taking place. So, the equilibrium will shift in the direction number of gaseous moles are less.

$N_2 (g) + 3H_2 (g)\rightleftharpoons 2NH_3 (g)$

On decreasing the volume the equilibrium will shift in right direction due to less number of gaseous moles on product side.

$2 Fe_2O_3 (s) \rightleftharpoons 4 Fe (s) + 3O_2 (g)$

On decreasing the volume the equilibrium will shift in left direction due to less number of gaseous moles on reactant side.

$2 SO_3 (g) \rightleftharpoons 2 SO_2 (g) + O_2 (g)$

On decreasing the volume the equilibrium will shift in left direction due to less number of gaseous moles on reactant side.

$H_2 (g) + Cl_2 (g) \rightleftharpoons 2 HCl (g)$

On decreasing the volume the equilibrium will shift in no direction due to same number of gaseous moles on both sides.

$2HI (g) \rightleftharpoons H_2 (g) + I_2 (g)$

On decreasing the volume the equilibrium will shift in no direction due to same number of gaseous moles on both sides.

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2 years ago

Which has more atoms: 1 mole of hydrogen atoms or 1 mole of carbon-12 atoms?

Lyrx [107]

Each mole has 6.02 x10^23 atoms so they have same atoms

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2 years ago

The rate constant of a first order reaction is 0.035 sec-1. How much of a 1.5 M sample of reactant would remain after 28 seconds

andrey2020 [161]

Answer:

0.56 M

Explanation:

Step 1: Given data

Rate constant (k): 0.035 s⁻¹

Initial concentration of the reactant ([A]₀): 1.5 M

Time elapsed (t): 28 s

Step 2: Calculate the amount of reactant ([A]) after 28 seconds

For a first-order kinetics, we will use the following expression.

ln [A] = ln [A]₀ - k × t

ln [A] = ln 1.5 - 0.035 s⁻¹ × 28 s

[A] = 0.56 M

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2 years ago

Which statement describes how heat flows from the coffee to the part of the spoon in the coffee?

lozanna [386]

Answer:

Heat flows from the coffee to the spoon through conduction

Explanation: I took did the lab assignment

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2 years ago

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