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1 year ago

14

The acceleration of an object is related to the net force exerted upon it and _ related

to the mass of the object.

1 answer:

Anettt [7]1 year ago

8 0

The acceleration of an object is directly related to the net force exerted upon it and inversely related to the mass of the object.

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Consider four different types of electromagnetic radiation: microwaves, infrared, ultraviolet, and X–rays. Arrange the types of

oksian1 [2.3K]

Answer:

A) from the lowest to the highest frequency:

Microwave - infrared - ultraviolet- X-ray

B) from the highest to the lowest energy:

X-ray - ultraviolet - infrared - microwave

Explanation: electromagnetic spectrum is the range of all types of electromagnetic radiation.

Radiation is the energy that travels and spreads out as it goes out.

4 0

2 years ago

An archer fish launches a droplet of water from the surface of a small lake at an angle of 70° above the horizontal. He is aimin

Norma-Jean [14]

Answer:

a). v=2776 m/s

Explanation:

The speed of the water droplet for the fish be successful is

Taking the distance in axis 'x' and 'y'

$x_{tx}=40cm\frac{1m}{100cm}=0.40m\\x_{ty}=23cm\frac{1m}{100cm}=0.23m$

The time is the velocity in axis 'x' with the angle 70 so

$t=\frac{0.40m}{v_{x}*cos(70)}$

Now using the time in terms of velocity the motion in axis 'y' can find the velocity to be the fish successful

$x_{yf}=x_{yo}+v_{o}*t+\frac{1}{2}*g*t^{2}\\0.23m=0.40m\frac{vo*sin(70)}{vo*cos(70)} +\frac{1}{2}*9.8*(\frac{0.40}{vo*cos(70)} )^{2}\\0.23m=0.40m*vo*tan(70)+4.9*(\frac{0.16m^{2} }{vo^{2} *cos(70)^{2} }) \\vo^{2}cos(70)^{2}=\frac{0.16m^{2} }{0.177}\\vo=\sqrt{\frac{0.9021}{cos(70)^{2}}} \\vo=2.776 \frac{m}{s}$

4 0

2 years ago

How are magnetic poles and electrical charges similar?

exis [7]

I believe the answer is a

3 0

2 years ago

Read 2 more answers

On February 15, 2013, a superbolide meteor (brighter than the Sun) entered Earth's atmosphere over Chelyabinsk, Russia, and expl

fredd [130]

Answer:

156.67 m/s

0.45676 times the speed of sound

Explanation:

Distance from the ground = 23.5 km = 23500 m

Time taken by the blast waves to reach the ground = $2\ minutes\ 30\ seconds=2\times 60+30=150\ s$

Spedd of the wave would be

$Speed=\dfrac{Distance}{Time}\\\Rightarrow v_b=\dfrac{23500}{150}\\\Rightarrow v-b=156.67\ m/s$

The velocity of the blast wave is 156.67 m/s

v = Velocity of sound = 343 m/s

$\dfrac{v_b}{v}=\dfrac{156.67}{343}\\\Rightarrow v_b=v\dfrac{156.67}{343}\\\Rightarrow v_b=0.45676v$

The blast wave is 0.45676 times the speed of sound

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3 years ago

Your teacher gives you a piece of cardboard with two pinholes on it, saying that they are separated by 205 μm ± 3%. In order to

wlad13 [49]

Answer:

m,lkj,mkn,njn

Explanation:because she is telling you to do a project

7 0

2 years ago