Answer:
$3.56
Step-by-step explanation:
mark me brainlest please
Answer:
Step-by-step explanation:
I have 30 coins, all nickels, dimes, and quarters, worth $4.60. There are two more dimes than quarters. How many of each kind of coin do I have.
..
let quarters be x
dimes = x+2
...
dimes + quarters = x+x+2=2x+2
...
nickels = 30-(2x+2)
...
5(30-(2x+2))+10(x+2)+25x=460
5(30-2x-2)+10x+20+25x=460
150-10x-10+10x+20+25x=460
160+25x=460
-160
25x=460-160
25x=300
/25
x=300/25
x=12 ---- quarters
x+2= 12+2=14 dimes
30-(2x+2)=4 nickels
...
check
4*5+14*10+12*25=20+140+300=460
199•25%=49.75
49.75+199=248.75
248.75•7.5%=18.65625
18.65625+248.75=267.40625
therefore the answer is $248.41
Ahh, i can see youre doing some programming. In C++ this output is -10
So -10
Answer:
22c+36
Step-by-step explanation:
3+11(2c+3)
3+22c+33
3+33+22c
36+22c or 22c+26