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2 years ago

15

What is the percent composition of Phosphorus in Li3PO3

1 answer:

Vilka [71]2 years ago

5 0

Answer:

you will get 17.983 g of lithium for every 100 g of lithium phosphate.

Explanation:

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How many secondary (2°) carbons are found in 5-ethyl-3,3,4-trimethylheptane??

Gelneren [198K]

5-Ethyl-3,3,4-trimethylheptane has 3 secondary carbon. A primary carbon written as 1° is a carbon that has one carbon atom attached to it. A secondary carbon written as 2° is a carbon attached to two other carbons, while a tertiary carbon written as 3° is a carbon attached to three other carbons.

6 0

2 years ago

Read 2 more answers

In a different experiment, the student uses a calorimeter which is perfectly insulated. She fills the calorimeter with 100.0 g o

alexdok [17]

Answer:

Explanation:

Mg + 2HCl = Mg Cl₂ + H₂

.594 g = .594 / 24.3

= .02444 mole

Heat evolved = msΔ T , m is mass of water ( solvant ) , s is specific heat of water , Δ T is rise in temperature

= 100 x 4.2 x ( 41.83 - 25 )

= 7068.6 J

.02444 mole of Mg evolves 7068.6 J of heat

1 mole of Mg evolves 7068.6 /.02444 J

= 289222.6 J

= 289 kJ .

Molar heat enthalpy = 289 kJ .

8 0

2 years ago

Describe the basic particle from which all ements are made

maxonik [38]

The answer for this question is: Atoms

7 0

2 years ago

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What is the theoretical yield of fluorenone if you oxidize 175 mg of fluorene?

My name is Ann [436]

Answer:

602 mg of CO₂ and 94.8 mg of H₂O

Explanation:

The<em> yield</em> is measured by the amount of each product produced by the reaction.

The chemical formula of <em>fluorene</em> is C₁₃H₁₀, and its molar mass is 166.223 g/mol.

The <em>oxidation</em>, also know as combustion, of this hydrocarbon is represented by the following balanced chemical equation:

$2C_{13}H_{10}+31O_2\rightarrow 26CO_2+10H_2O$

To calculate the yield follow these steps:

<u>1. Mole ratio</u>

$2molC_{13}H_{10}:31molO_2:26molCO_2:10molH_2O$

<u />

<u>2. Convert 175mg of fluorene to number of moles</u>

$175mg/times 1g/1,000mg=0.175g$

Number of moles = mass in grams / molar mass

$\text{number of moles}=0.175g/166.223g/mol=0.0010528mol$

<u>3. Set a proportion for each product of the reaction</u>

a) <u>For CO₂</u>

i) number of moles

$2molC_{10}H_{13}/26molCO_2=0.0010528molC_{10}H{13}/x$

$x=0.0010528molC_{10}H_{13}\times 26molCO_2/2molC_{10}H_{13}=0.013686molCO_2$

ii) mass in grams

The molar mass of CO₂ is 44.01g/mol

mass = number of moles × molar mass

mass = 0.013686 moles × 44.01 g/mol = 0.602 g = 602mg

b) <u>For H₂O</u>

i) number of moles

$0.0010528molC_{10}H_{13}\times10molH_2O/2molC_{10}H_{13}=0.00526molH_2O$

ii) mass in grams

The molar mass of H₂O is 18.015g/mol

mass = number of moles × molar mass

mass = 0.00526 moles × 18.015 g/mol = 0.0948mg = 94.8 mg

4 0

2 years ago

Which would be an example of a compound?<br> oxygen<br> carbon dioxide<br> sand<br> carbon

GenaCL600 [577]

Answer:

carbondioxide is an example of compound.

4 0

3 years ago