Answer:
0.07%
Step-by-step explanation:
This equation is solving for what percentage of 100 kg is 0.07 kg.
1. Set up the equation
=
0.07 kg out of 100 kg is equal to x out of 100 because x represents the percentage and percentages are out of 100.
2. Solve by cross multiplying
100x = 7
3. Solve for x by dividing both sides by 100
x = 0.07
The answer is 0.07%
Answer:
<em>(1, - 2) </em>
Step-by-step explanation:
2x - y = 4
3x + y = 1
A = = 2(1) - 3( - 1) =2 + 3 = 5
= = 4(1) - 1(- 1) = 4 + 1 = 5
= = 2(1) - 4(3) = 2 - 12 = - 10
<em>x </em>= =<em> 1</em>
<em>y </em>= = <em>- 2</em>
<em>(1, - 2)</em>
Answer: tea = 15 rupees per kg
sugar= 3 rupees per kg
Step-by-step explanation:
Hi, to answer this question we have to write a system of equations with the information given:
<em>"Two kg of tea and 3 kg of sugar cost rupees 39 in january 1997":
</em>
2 t + 3 s =39 (a)
Where:
- t= price of 1 kg of tea
- s = price of 1 kg of sugar
<em>"in march 1997 the price of the tea increased by 25% (1.25)and the price of the sugar increased by 20%(1.20) and the same quantity of tea and sugar cost rupees 48.30.
"</em>
2(t1.25)+3(s1.2) = 48.30 (b)
- <em>Solving for t in (b)
</em>
2t =39-3s
t = (39 -3s)/2
t = 19.5-1.5s
- <em>Replacing the value of t in (b)
</em>
2 x ((19.5-1.5s)1.25)+ 3 ( 1.2s) =48.30
2x ( 24.375 -1.875s) +3.6s =48.30
48.75 -3.75s+3.6s= 48.30
48.75-48.30 = 3.75s-3.6s
0.45= 0.15s
0.45/0.15 =s
3 =s
- <em>Replacing the value of s in (a)
</em>
2 t + 3 (3) =39
2 t + 9 =39
2 t =39 -9
2 t =30
t = 30/2
t= 15
Prices in january:
tea = 15 rupees per kg
sugar= 3 rupees per kg
Feel free to ask for more if needed or if you did not understand something.
Answer:
21N:7m/s
? :10m/s
21x10=210
210÷7=30N
Your final answer is 30N
Step-by-step explanation:
This is called direct propotion
it involves close multiplication
11z/16+7z/8=5/16
(11z+14z)/16=5/16
25z=5
z=5/25=1/5