(b+3)1/2+b1/2=3 A. b=0 and b= 2/3 B. b=1/4 and b=2 C. b=1 D. b=3

Find the equation of the line specified. The slope is 7, and it passes through ( 8, 6).

STALIN [3.7K]

Answer:

The answer is A

Step-by-step explanation:

Given that the equation of line is y = mx + c and the slope is 7 :

y = 7x + c

By substituting the coordinate(8,6) into the equation, in order to find the value of c:

6 = 7(8) + c

6 = 56 + c

c = 6 - 56

= -50

y = 7x - 50

(Hope this can help)

6 0

2 years ago

Solve for m in V = 3x + 2m - y.

jok3333 [9.3K]

Answer:

$\large\boxed{m=\dfrac{V+y-3x}{2}}$

Step-by-step explanation:

$3x+2m-y=V\qquad\text{add}\ y\ \text{to both sides}\\\\3x+2m-y+y=V+y\\\\3x+2m=V+y\qquad\text{subtract}\ 3x\ \text{From both sides}\\\\3x-3x+2m=V+y-3x\\\\2m=V+y-3x\qquad\text{divide both sides by 2}\\\\\dfrac{2m}{2}=\dfrac{V+y-3x}{2}\\\\m=\dfrac{V+y-3x}{2}$

8 0

2 years ago

X = 8,1,3,3,5

Ghella [55]

Answer:

2.600 = Exact

2.6 = Base Form

Step-by-step explanation:

?

6 0

1 year ago

Kerry has a bag containing white and yellow marbles. Kerry randomly selects one marble, records the result, and returns the marb

dexar [7]

Answer:

The probability that next selection is yellow marble = 63% .

Step-by-step explanation:

Given the selection of yellow marbles = 41 times.

The selection of white marble = 24 times.

Total number of selections made = 65

Now calculate the probability that the next selection will be the yellow marble. Therefore, the probability of getting yellow marble can be determined by dividing the yellow selection by total number of selections.

$\text{P(yellow)} = \frac{ \text{The selection of yellow marbles} }{ \text{ Total number of slections }} \\\text{P(yellow)} = \frac{41}{65} = 0.63 \ or \ 63 \ percent$

7 0

2 years ago

The weight of an adult swan is normally distributed with a mean of 26 pounds and a standard deviation of 7.2 pounds. A farmer ra

Snezhnost [94]

Let $X$ denote the random variable for the weight of a swan. Then each swan in the sample of 36 selected by the farmer can be assigned a weight denoted by $X_1,\ldots,X_{36}$ , each independently and identically distributed with distribution $X_i\sim\mathcal N(26,7.2)$ .

You want to find

$\mathbb P(X_1+\cdots+X_{36}>1000)=\mathbb P\left(\displaystyle\sum_{i=1}^{36}X_i>1000\right)$

Note that the left side is 36 times the average of the weights of the swans in the sample, i.e. the probability above is equivalent to

$\mathbb P\left(36\displaystyle\sum_{i=1}^{36}\frac{X_i}{36}>1000\right)=\mathbb P\left(\overline X>\dfrac{1000}{36}\right)$

Recall that if $X\sim\mathcal N(\mu,\sigma)$ , then the sampling distribution $\overline X=\displaystyle\sum_{i=1}^n\frac{X_i}n\sim\mathcal N\left(\mu,\dfrac\sigma{\sqrt n}\right)$ with $n$ being the size of the sample.

Transforming to the standard normal distribution, you have

$Z=\dfrac{\overline X-\mu_{\overline X}}{\sigma_{\overline X}}=\sqrt n\dfrac{\overline X-\mu}{\sigma}$

so that in this case,

$Z=6\dfrac{\overline X-26}{7.2}$

and the probability is equivalent to

$\mathbb P\left(\overline X>\dfrac{1000}{36}\right)=\mathbb P\left(6\dfrac{\overline X-26}{7.2}>6\dfrac{\frac{1000}{36}-26}{7.2}\right)$
$=\mathbb P(Z>1.481)\approx0.0693$

5 0

2 years ago