Can somebody plz help give the correct equations for both of the word problems (only if u done this before) thx :D
2 answers:
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Answer: See below
Step-by-step explanation:
For this problem, we are given four functions, and their domains. All we have to do is figure out which equation we want to plug x into and solve.
f(-20)
For this first problem, we have x=-20. Then we can eliminate equations 1, 2, 4. We know equation 3 is the correct one because it says x<-12. -20 is less than -12. Therefore we plug in x=-20 to the third equation.
f(-20)=3(-20)-7 [multiply]
f(-20)=-60-7 [subtract]
f(-20)=-67
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f(0)
For this problem, we have x=0. Then we can eliminate equations 1, 2, 3. We know equation 4 is the correct one because it says x∈{-15, -12, 0, 10}. This means x has to be either one of the four numbers listed in the parentheses. We see that x=0 is in there. Therefore we plug in x=0 to the fourth equation.
f(0)=11-|-0-1| [subtract]
f(0)=11-|-1| [absolute value]
f(0)=11-1 [subtract]
f(0)=10
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f(15)
For this problem, we have x=15. Then we can eliminate equations 2, 3, 4. We know equation 1 is the correct one because it says x>10. This means x has to be greater than 10. 15 is greater than 10. Therefore we plug in x=15 to the first equation.
[add]
[absolute value]
[subtract]
<h3>log [ (√3)(2 - x)/(3x) ] = log (2 - x) - ¹/₂ log 3 - log x</h3><h3>Further explanation</h3>
Let's recall following formula about Exponents and Surds:
<em>Let us tackle the problem!</em>
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Grade: High School
Subject: Mathematics
Chapter: Exponents and Surds
Keywords: Power , Multiplication , Division , Exponent , Surd , Negative , Postive , Value , Equivalent , Perfect , Square , Factor.