t = mr^2/3
Divide both sides by r^2/3
m = t / r^2/3
Answer:
// C++ Program to arithmetic operationf on 2 Numbers using Recursion
// Comments are used for explanatory purpose
#include <bits/stdc++.h>
using namespace std;
// add10 recursive function to perform arithmetic operations
int add10(int m, int n)
{
return (m + product(n, 10)); //Result of m + n * 10
return 0;
}
// Main Methods Starts here
int main()
{
int m, n; // 2 Variables m and n declared as integer
cin>>m; // accept input for m
cin>>n; // accept input for n
cout << "Result : "<<add10(m,n); // Print results which is calculated by m + 10 * n
return 0;
}
Since 1/2=0.5 and 1/8=0.125, we have 2.5, 2.4, 2.35, and 2.125. The first number we look for is the one to the left, and they're all the same, so that doesn't necessarily help. Next, we have a 5, 4, 3, and 1. They're already in order from greatest to least, so that's awesome!
When you use a tens fact you round to the nearest ten and 15-8=7. The nearest ten to seven is 10
Answer:10
3.2 × 10-4 3.2 × 10-5 3.2 × 10-7 32 × 10-4