Answer:
- <em>Abbie’s acceleration is (1/2) Zak’s acceleration.</em>
Explanation
1. <u>Data</u>:
a) ω = constant
b) Abbie: r₁ = 1 m
c) Zak: r₂ = 2 m
d) Ac₁ = ? Ac₂
2. <u>Formulae</u>
3. <u>Solution</u>:
a) Abbie:
b) Zack:
c) Divide Ac₁ / Ac₂
- Ac₁ / Ac₂ = ω² (1m) / [ω² (2m) ] = 1/2
⇒ Ac₁ = (1/2) Ac₂ = Ac₂ / 2 = 0.5 Ac₂
Answer with Explanation:
We are given that
Charge on proton,q=
a.We have to find the electric potential of the proton at the position of the electron.
We know that the electric potential
Where
B.Potential energy of electron,U=
Where
Charge on electron
=Charge on proton
Using the formula
Solution:
With reference to Fig. 1
Let 'x' be the distance from the wall
Then for DAC:
⇒
Now for the BAC:
⇒
Now, differentiating w.r.t x:
For maximum angle, = 0
Now,
0 = [/tex]\frac{d}{dx}[tan^{-1} \frac{d + h}{x} - tan^{-1} \frac{d}{x}][/tex]
0 =
After solving the above eqn, we get
x =
The observer should stand at a distance equal to x =