Answer:
A = 0.8 litres
B = 0.7 litres
C = 0.5 litres
D = 0.2 litres
Step-by-step explanation
Here's what we know:
1. Jug A = B + .1 litres
2. Jug C = B - 200 (or 0.2 litres)
3. Jug D = .25 x A
4. Jug A + Jug B = 1.5 litres
In problem 1, we learned that Jug A has .1 litres more than Jug B and in problem 4, the two of them added together are 1.5 litres. To solve this we can combine the problems.
B + .1 litres + B = 1.5 litres
2B + .1 = 1.5
Subtract .01 from each side and you have 2B = 1.4
Divide each side by 2 and you have B = 0.7 litres
Plug this info into problem 1 and you can solve for A. (0.7 + 0.1 = 0.8)
Plug this info into problem 2 and you can solve for C. (0.7 - 0.2 = 0.5)
Since you have A, you can use that info to solve problem 3 (0.25 x 0.8 = 0.2)
First : x=-5-y and then put x in the phrase above
we are given
differential equation as
we are given
Firstly, we will find y' , y'' and y'''
those are first , second and third derivative
First derivative is
Second derivative is
Third derivative is
now, we can plug these values into differential equation
and we get
now, we can factor out common terms
we can move that term on right side
now, we can factor out
now, we can set them equal
so, we will get
...............Answer
Answer:
C.
Step-by-step explanation:
Line CD has a slope of -5/3 and the negative reciprocal of 3/5. The slope for the line given is 3/5 so the slopes are right. Then look at the y-intercept of the line given: (0,-2) Go up 3 and over 5 and you can see it pass through the line CD making C the answer.
Answer:
5(1248 lb/horse + t lb) ≤ 8000 lb
Step-by-step explanation:
One way to do this is to find the average weight of the 5 horses:
It is:
6,240 lb
---------------- = 1248 lb/horse
5 horses
and to this, for each horse, we must add t lbs tack.
Thus, 5(1248 lb/horse + t lb) ≤ 8000 lb
would be an appropriate inequality.
Please note that your question mentions "the following inequalities;" that means you are expected to share them! Please do so next time. Thanks.