> multiply the second equation by 2 and add it to the first equation.
2(-6x - 7y = -10)
-12x -14y = -20
8x + 14y = 4
-12x - 14y = -20
--------------------
- 4x + 0 = - 16
x = -16/-4
x = 4
> use x = 4 in either equation to find y
8(4) + 14y = 4
32 + 14y = 4
14y = 4 - 32
14y = -28
y = -28/14
y = -2
Answer:
70 yd.
Step-by-step explanation:
The three streets at the intersection form a right triangle.
For a right triangle, the length of the longest side (called hypothenuse) is given by Pythagorean's theorem:
where
x is the length of the 1st side
y is the length of the 2nd side
h is the length of the hypothenuse
Here we want to find the hypothenuse.
We have:
x = 42 yd (length of the 1st side)
y = 56 yd (length of the 2nd side)
Substituting, we find h:
Answer:
A (0,3)
Step-by-step explanation:
The given trapezoid has vertices:
(0,6), (7,12), (7,9) and (0,12).
We want to choose from the given options, a point that is a vertex for the image produced by a dilation about the origin with a scale factor of 1/2.
Note that the mapping for such a dilation is:
This implies that:
Therefore correct choice is (0,3)
Answer:
(f + g)(x) = 3x² + (7/3)x - 8
Step-by-step explanation:
To find (f + g)(x), you need to add both the f(x) and g(x) equations together.
f(x) = x/3 - 2 ..... which is equal to ... f(x) = (1/3)x - 2
g(x) = 3x² + 2x - 6
(f + g)(x) = ((1/3)x - 2) + (3x² + 2x - 6) <----- Add both equations
(f + g)(x) = 3x² + (1/3)x + 2x - 2 - 6 <----- Rearrange (2 = 6/3)
(f + g)(x) = 3x² + (7/3)x - 8 <----- Simplify similar terms