Given:
Temperature in the morning = 6°F.
By the late afternoon, the temperature had dropped 9°F.
To find:
The temperature by the late afternoon.
Solution:
Temperature by the late afternoon = Morning temperature - Dropped temperature
Using the given values and the above formula, we get
Temperature by the late afternoon = 6°F - 9°F
Temperature by the late afternoon = -3°F
Therefore, the temperature by the late afternoon is -3°F.
Answer:
y = 110°
Step-by-step explanation:
The inscribed angle CHF is half the measure of its intercepted arc CDF
The 3 arcs in the circle = 360°, thus
arc CDF = 360° - 160° - 60° = 140°, so
∠ CHF = 0.5 × 140° = 70°
∠ CHF and ∠ y are adjacent angles and supplementary, thus
y = 180° - 70° = 110°
15% of R560 - 15% of R500
=> 0.15 × 560 – 0.15 × 500
=> 0.15 ( 560–500)
=> 0.15 × 60
=> Rs. 9
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Well you'd see if it's closer to 10000 or 20000.
In this case it would round to 20000.