I'll do the first two to get you started
===============================================
Problem 1
A = 3 = starting value
B = 10 = ending value
C = percent change
C = [ (B - A)/A ] * 100%
C = [ (10-3)/3 ] * 100%
C = (7/3) * 100%
C = 2.3333333 * 100%
C = 233.33333%
C = 233.3%
The positive C value means we have a percent increase. If C was negative, then we'd have a percent decrease.
<h3>Answer: 233.3% increase</h3>
===============================================
Problem 2
A = 9 = start value
B = 20 = end value
C = percent change
C = [ (B - A)/A ] * 100%
C = [ (20-9)/9 ] * 100%
C = (11/9)*100%
C = 1.2222222222*100%
C = 122.22222222%
C = 122.2%
<h3>Answer: 122.2% increase</h3>
The two given angles are vertical angles and equal each other:
3x + 50 = 6x -10
Now solve for x:
Subtract 3x from both sides:
50 = 3x -10
Add 10 to both sides:
60 = 3x
Divide both sides by 3
X = 20
Step-by-step explanation:
any rational number can be expressed as a/b, with a and b being integer numbers, and b different to 0.
-7 = -7/1 rational
sqrt(10) irrational (because there is no rational number multiplied by itself that results in 10)
sqrt(16) = sqrt(4×4) = 4 = 4/1 rational
52% = 52/100 rational
1.235 = 1235/1000 rational
Answer:
B has a smaller initial population of 500
Step-by-step explanation:
Given
See attachment for complete question
Required
The bacteria with the smaller initial population
The initial population is at x = 0
For bacteria A;
when 
For bacteria B, we have:
Substitute 0 for x
So; when x = 0
and
Because; 500 < 600
We can conclude that B has a smaller initial population of 500
