<span>The general form of quadratic equation with real
coefficients and leading coefficient 1, has x = -bi as a root
=> x = <u>-b + </u></span><u>√ b^2 – 4 ac</u><span>
2a
It is also written as:
=> ax^2 + bx + c = 0
Quadratic equation involves unknown numbers which is x, the numbers which a, b
and c are called coeffecients.
There are also quadratic factorization where you factor the polynomial give to
be able to get the value of the equation.</span>
Pascals triangle to the 6th:
1 x^0
1 1 x^1
1 2 1 x^2
1 3 3 1 x^3
1 4 6 4 1 x^4
1 5 10 10 5 1 x^5
1 6 15 20 15 6 1 x^6<span>
</span>the problem is to the 6th power so your going to use the 6th row of pascals triangle (don't count the first row). these numbers represent the coefficients of the variables
1(d-5y)^6 + 6(d-5y)^5 + 15(d-5y)^4 + 20(d-5y)^3 + 15(d-5y)^2 + 6(d-5y) + 1
then simplify
<span>lengths are in ratio 1:3
areas are in ratio
1 : 3</span>²<span> = 1: 9
area of ADG = 9 x 42 = 378 </span>
Answer:
0
Step-by-step explanation:
-9 x 0 is 0 and dividing anything with 0 is 0
Acute angle i think about 60
