Answer:
174 ft²
Step-by-step explanation:
Assuming you're interested in the area of the figure, you can compute it as the sum of the areas of the triangle and rectangle.
The unknown side of the triangle can be figured from the overall dimension of the rectangle and the two lengths that are not part of the triangle base:
6 ft + triangle base + 6 ft = 18 ft
triangle base = 18 ft - 12 ft = 6 ft
Then the area of the triangle is ...
A = 1/2bh = 1/2(6 ft)(4 ft) = 12 ft²
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Of course, the area of the rectangle is the product of its length and width:
A = LW = (18 ft)(9 ft) = 162 ft²
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The total area of the figure is the sum of these:
area = triangle area + rectangle area
area = 12 ft² +162 ft²
area = 174 ft²
Slope-intercept form is:
y = mx + b
"m" is the slope, "b" is the y-intercept (the y value when x = 0)
(there is probably another way to do this, but I will be doing it this way)
Isolate the "y" in the equation
3x + 4y = 12 Subtract 3x on both sides
4y = 12 - 3x Divide 4 on both sides
or The slope is -3/4
For lines to be parallel, they have to have the SAME slope. The given line's slope is -3/4, so the slope of the parallel line is also
1) Let's solve for x, writing this equation.
3x +8*59 =0
3x +472=0 <em>Subtract 472 from both sides</em>
3x = -472
x= -472/3 or -157.33
2) So the answer is x= -472/3
Answer:
f(x) > 0 over the interval
Step-by-step explanation:
If f(x) is a continuous function, and that all the critical points of behavior change are described by the given information, then we can say that the function crossed the x axis to reach a minimum value of -12 at the point x=-2.5, then as x increases it ascends to a maximum value of -3 for x = 0 (which is also its y-axis crossing) and therefore probably a local maximum.
Then the function was above the x axis (larger than zero) from , until it crossed the x axis (becoming then negative) at the point x = -4. So the function was positive (larger than zero) in such interval.
There is no such type of unique assertion regarding the positive or negative value of the function when one extends the interval from to -3, since between the values -4 and -3 the function adopts negative values.