If your scale factor is 3/4, how will the scaled copy compare to the original?

1 answer:

3 0

A scaled copy with the scale factor being 3/4 it would be smaller because it’s less than one so whenever there is a fraction that’s less than one then the shape would be smaller aswell

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Write a quadratic function h whose zeros are - 6 and -5 h (x) =

ANTONII [103]

Answer:

h(x)= x^2+11x+30

Step-by-step explanation:

A quadratic function is in the form h(x) = ax^2 + bx + c.

Since the zeros are -6 and -5, take the opposite signs and add them to the variable x separately.

It should look like this: h(x)= (x+6)(x+5)

Since this is the factored form, we have to solve this equation further.

h(x)= (x+6)(x+5)

h(x)= x^2+6x+5x+30

h(x)= x^2+11x+30

4 0

2 years ago

If <img src="https://tex.z-dn.net/?f=f%28x%29%3Dx%5E2-2" id="TexFormula1" title="f(x)=x^2-2" alt="f(x)=x^2-2" align="absmiddle"

jek_recluse [69]

Answer:

$\boxed{f(6) = 34}$

Step-by-step explanation:

Composition of functions occurs when we have two functions normally written similar or exactly like f(x) & g(x) - you can have any coefficients to the (x), but the most commonly seen are f(x) and g(x). They are written as either f(g(x)) or (f o g)(x). Because our composition is written as $(f \circ g)(2)$ , we are replacing the x values in the g(x) function with 2 and simplifying the expression.

$g(2) = 3(2)$

$g(2) = 6$

Now, because we are composing the functions, this value we have solved for now replaces the x-values in the f(x) function. So, f(x) becomes f(6), and we use the same manner as above to simplify.

$f(6) = (6)^2-2$