Andre and scott share the driving on a trip. Scott drives 7 miles more than three times tge distance Andre drives. If the trip i s 111 miles, what distance did scott drive?
2 answers:
Answer:
Step-by-step explanation:
What we know is that A + S = 111. That is, the miles Andre drove plus the miles Scott drove totalled 111 miles. What we also know is that Scott drove quite a bit more than Andre did. Scott drove 7 miles more that ( +7 ) 3 times the number of miles Andrea drove. That looks like this algebraically:
S = 3A + 7
Now we can sub in that value for S to the original equation:
If A + S = 111 and S = 3A + 7, then
A + 3A + 7 = 111 and
4A + 7 = 111 and
4A = 104 so
A = 26 and
S = 3(26) + 7 so
S = 85 miles.
Scott drove 85 miles.
Answer:
Scott drove 89.5 miles.
Step-by-step explanation:
Represent Andre's distance by a and Scott's by s. Then s = 3a + 7.
Then the total distance driven by both is a + 3a + 7 = 117 (miles), or
4a - 110 miles, or a = 27.5 miles. Thus, s = 3(27.5) + 7 = 89.5 miles .
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