Answer:
The wide of the city is 10.7km
Step-by-step explanation:
To solve this we first have to know the formula to calculate the area of a square
a = area = 115 km²
s = side
a = s * s
now we replace with the known values
115 km² = s * s
115 km² = s²
√(115 km²) = s
10.724km = s
Round to the nearest tenth
s = 10.724km = 10.7km
The wide of the city is 10.7km
Answer:
the answer would be -2, -6 and if you need more help i believe you can work up to it
Step-by-step explanation:
Answer:
Rhombus
Step-by-step explanation:
The given points are A(−5, 6), B(−1, 8), C(3, 6), D(−1, 4).
We use the distance formula to find the length of AB.
The length of AD is
The length of BC is:
The length of CD is
Since all sides are congruent the quadrilateral could be a rhombus or a square.
Slope of AB
Slope of BC
Since the slopes of the adjacent sides are not negative reciprocals of each other, the quadrilateral cannot be a square. It is a rhombus
We have been given a right angled triangle, hypotenuse is known, and angle has been given. we need to find the adjacent side to the angle.
we use trigonometry ratios.
the ratio where we relate the hypotenuse and adjacent side is the cosine.
cos θ = adjacent side / hypotenuse
where θ = 39°
hypotenuse - 17 m
adjacent side - x
we need to solve for x
cos 39° = x / 17
cos 39° = 0.77
0.7771 = x/17
x = 0.7771 x 17
x = 13.21 m
distance from Roman's feet to the base of the pole is 13.21