Answer : The value of activation energy for this reaction is 108.318 kJ/mol
Explanation :
The Arrhenius equation is written as:
Taking logarithm on both the sides, we get:
............(1)
where,
k = rate constant =
Ea = activation energy = ?
T = temperature = 435 K
R = gas constant = 8.314 J/K.mole
A = pre-exponential factor =
Now we have to calculate the value of rate constant by putting the given values in equation 1, we get:
Therefore, the value of activation energy for this reaction is 108.318 kJ/mol
Answer:
Molecules with three electron pairs
Explanation:
=>
Explanation:
a) Both A and R are true and R is the correct
explanation of A.
Answer:
0.2 is conpound Co2 STP.
Explanation:
on combustion of 0.2 gm of organic compound gave 0.147g of CO2, 0.12g of H2O and 74.6 ml of nitrogen gas at STP. Find emperical formula of compound.?