Hello Again!
What you want to do first is add 4 to -4 and to -13. After doing so, you'll equation will look a little something like this...
-3x=9
You'll then want to divide both -3 and 9 by -3. After doing so, the equation will look like this...
x=-3
Your answer is x=-3
I hope this helps
Answer:
Step-by-step explanation:
1. A car requires 22 litres of petrol to travel a distance of 259.6 km
what is the distance that the car can travel on 63 ltr of petrol
22ltr = 259.6km
63ltr=
cross multiply
{63 x 259.6}/22 = 16354.8/22 = 743.4 km
A car requires 22 litres of petrol to travel a distance of 259.6 km, it would require 63 ltr of petrol to travel 743.4km
2. To travel a distance of 2013.2 km
we would need to calculate the amount of fuel
A car requires 22 litres of petrol to travel a distance of 259.6 km
what amount of fuel would it require to travel 2013.2km
22ltr = 259.6km
xltr = 2013.2km
x is the value of petrol to cover 2013.2km
cross multiply
(2013.2 x 22)/259.6
44290.4/259.6 = 170.610169492≈170.6 ltr
A car requires 22 litres of petrol to travel a distance of 259.6 km, it would require 170.6 ltr of petrol to travel 2013.2km
if 1ltr is $1.99
170.6 ltr is (170.6 x 1.99)/1 = $339.494≈$339.5
The price of fuel consumed for 2013.2 km at 1 liter of petrol at $1.99 is $339.5
Answer:
The equation you are given is a quadratic. The standard form of a quadratic is y = a(x-h)2 + k where (h,k) is the vertex of the graph, which is a parabola. Vertically moving the graph 4 units upward means that you are moving k +4 units.
y = a(x-h)2 + k standard form
y = 5x2 - 4 original equation
y = 5(x-0)2 - 4 re-written in standard form
h = 0 k = -4
Four (4) units up is k + 4--->-4 + 4 = 0.
Therefore, f(x) = 5x2 + 0--->f(x) = 5x2.
Step-by-step explanation:
hope this helps
plz mark brainliest
Answer:
Step-by-step explanation:
(i) x+2y=4
(ii) x=4-2y
(iii) 2x-2y=5
substituting (ii) in (iii)
2x-2y=5
2(4-2y)-2y=5
8-4y-2y=5
-6y=5-8
-6y=-3
(iv) y=
substituting (iv) in (ii)
x=4-2y
x=4-2×
x=4-1
x=3
∴ B.(3,)
HOPE IT HELPS YOU!!!!
Answer:
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