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2 years ago

Create an equation in point slope form of the following graph.

Mathematics

1 answer:

blondinia [14]2 years ago

4 0

Answer:

jus sad u need to start paying attenion to class but the anwser is nun of yp bu

Step-by-step explanation:

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You deposit $2000 into an account that pays 6% compounded monthly. a. How much money will you have in the account after 1 year?

Masteriza [31]

We have a deposit of $2000 into an account that pays 6% compounded monthly, after a year we will have:

$\begin{gathered} \text{account}_{\text{year}}=2000\cdot(1+\frac{6}{100})^{12} \\ \text{account}_{\text{year}}=4024.4 \end{gathered}$

The effective annual yield (EAY) will be:

$\text{EAY}=\frac{account_{year}}{2000}-1=\frac{4024.14}{2000}-1=1.0122$

The EAY is 101.22%

8 0

3 months ago

Which of the following is a solution of z^5 = 1 + √3 i?

nordsb [41]

Answer:

Option 2 is right

Step-by-step explanation:

Given that

$z^5=1+\sqrt{3} i$

We can write this in polar form with modulus and radius

$|z^5|= \sqrt{1+3} =2\\tan of Angle t =\sqrt{3} \\$

Hence angle = 60 degrees and

$|z^5|= 2(cos60+isin60)$

Since we have got 5 roots for z, we can write 60, 420, 780, etc. with periods of 360

Using Demoivre theorem we get 5th root would be

5th root of 2 multiplied by 1/5 th of 60, 420, 780,....

$z= \sqrt[5]{2} (cos12+isin12)\\z=\sqrt[5]{2} (cos84+isin84)\\\\z=\sqrt[5]{2} (cos156+isin156)\\\\z=\sqrt[5]{2} (cos228+isin228)\\\\z=\sqrt[5]{2} (cos300+isin300)\\$

Out of these only 2nd option suits our answer

Hence answer is Option 2.

8 0

2 years ago

Enter the correct answer in the box. solve the equation x2 − 16x 54 = 0 by completing the square. fill in the values of a and b

poizon [28]

The roots of the given polynomials exist $x=8+\sqrt{10}$ , and $x=8-\sqrt{10}$ .

<h3>What is the formula of the quadratic equation?</h3>

For a quadratic equation of the form $a x^{2}+b x+c=0$ the solutions are

$x_{1,2}=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

Therefore by using the formula we have

$x^{2}-16 x+54=0$$

Let, a = 1, b = -16 and c = 54

Substitute the values in the above equation, and we get

$x_{1,2}=\frac{-(-16) \pm \sqrt{(-16)^{2}-4 \cdot 1 \cdot 54}}{2 \cdot 1}$$

simplifying the equation, we get

$$&x_{1,2}=\frac{-(-16) \pm 2 \sqrt{10}}{2 \cdot 1} \\$

$$&x_{1}=\frac{-(-16)+2 \sqrt{10}}{2 \cdot 1}, x_{2}=\frac{-(-16)-2 \sqrt{10}}{2 \cdot 1} \\$

$$&x=8+\sqrt{10}, x=8-\sqrt{10}$

Therefore, the roots of the given polynomials are $x=8+\sqrt{10}$ , and

$x=8-\sqrt{10}$ .

To learn more about quadratic equations refer to:

brainly.com/question/1214333

#SPJ4

3 0

9 months ago

Read 2 more answers

Quincy claims that if 80 coats are sold, the outside temperature is likely to be about 42°

nikklg [1K]

No. Quincy should have used the trend line to find the corresponding x value when y=80.

6 0

2 years ago

Read 2 more answers

X^2 - 16 = 0 by extracting the square root

scoray [572]

Answer:

{-4, 4}

Step-by-step explanation:

x² - 16 = 0
x² = 16
x = √16
x = ± 4

6 0

1 year ago