Answer:
y+3=-11/7(x-2)
Step-by-step explanation:
y-y1=m(x-x1)
m=(y2-y1)/(x2-x1)
m=(8-(-3))/(-5-2)
m=(8+3)/(-7)
m=11/-7
m=-11/7
y-(-3)=-11/7(x-2)
y+3=-11/7(x-2)
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Hello!
So you will use the Pythagorean Theron equation which is Asquare + bsquare=C square
Plug in what you are given to find the missing piece
A square+ (2.6)square= (6.2) square
Asquare+ 6.76= 38.44
(Subtract 6.76to both sides to isolate A)
Asquare= 31.68
(Take the square root of both sides to find out what A is)
A=5.628
Pythagorean Theorem: a^2+b^2=c^2
(9)^2 + b^2 = (23)^2
81 + b^2 = 529
b^2 = 529 - 81
b^2 = 448
b^2 =
b = 21.2