Answer:
Step-by-step explanation:
The altitude to the hypotenuse of a right triangle create two smaller triangles, all of which are similar to the original. This means corresponding sides are proportional.
3. Using the above relationship, ...
short-side/hypotenuse = 8/y = y/(8+23)
y^2 = 8·31
y = 2√62
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long-side/hypotenuse = z/(8+23) = 23/z
z^2 = 23·31
z = √713
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short-side/long-side = 8/x = x/23
x^2 = 8·23
x = 2√46
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4. The picture is fuzzy, but we think the lengths are 25 and 5. If they're something else, use the appropriate numbers. Using the same relations we used for problem 3,
y = √(5·25) = 5√5 . . . . . . . = √(short segment × hypotenuse)
z = √(20·25) = 10√5 . . . . . = √(long segment × hypotenuse)
x = √(5·20) = 10 . . . . . . . . . = √(short segment × long segment)
Answer:
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Step-by-step explanation:
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Answer:
100㏑²
Step-by-step explanation;
first of all you find the base using the pythagoras theorem
that is, √13² - 12² =√25 = 5
so 5 is the base of the right angle in the big isoceles triangle
so the base of the isoceles triangle is 10 [5 + 5]
so for the first triangle the area is 60㏑²
the second triangle is 40㏑²
therefore 60 + 40 = 100㏑²
Answer:
-66
Step-by-step explanation:
11 × (-6) = -66