<span>No simple interest, only compound interest.</span>
Given that the function is 
We need to determine the average rate of change over the interval 
<u>Value of f(x) when x = 0:</u>
Substituting x = 0 in the function , we have;
Thus, the value of f(0) is 7.
<u>Value of f(x) when x = 5:</u>
Substituting x = 5 in the function , we have;
Thus, the value of f(5) is 2.
<u>Average rate of change:</u>
The average rate of change can be determined using the formula,
where 
and 
Thus, we have;
Thus, the average rate of change over the interval is -1.
Answer:
Quadratic equations are similar to exponential equations by having a curve in the graph. Algebraically, linear functions are polynomial functions with a highest exponent of one, exponential functions have a variable in the exponent, and quadratic functions are polynomial functions with a highest exponent of two.
Present value of annuity PV = P(1 - (1 + r/t)^-nt) / (r/t)
where: p is the monthly payment, r is the APR = 14.12% = 0.1412, t is the number of payments in one year = 12, n is the number of years = 2.
1,120.87 = P(1 - (1 + 0.1412/12)^(-2 x 12)) / (0.1412 / 12)
0.1412(1120.87) = 12P(1 - (1 + 0.1412/12)^-24)
P = 0.1412(1120.87) / 12(1 - (1 + 0.1412/12)^-24) = $53.88
Minimum monthly payment = 3.15% of 1120.87(1 + 0.1412/12) = 0.0315 x 1120.87(1 + 0.1412/12) = $35.72
Therefore, his first payment will be greater than the minimum payment by 53.88 - 35.72 = $18.16
Answer:-3,4
Step-by-step explanation:
