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2 years ago

Brainly for questions 4 & 5

Mathematics

1 answer:

dimulka [17.4K]2 years ago

7 0

Answer:

its a quiz you might get banned

Step-by-step explanation:

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First year of high school heh need a little help

Luba_88 [7]

Answer:

(12 + 3x)x

Step-by-step explanation:

(12 + 3)x = 12x + 3x = 15x

(12 + 3x)x = 12x + 3x²

15x

12x + 3x = 15x

They all equal 15x except for (12 + 3x)x

7 0

2 years ago

Write the composite function in the form f(g(x)). [Identify the inner function u = g(x) and the outer function y = f(u).] y = ta

Irina-Kira [14]

Answer:

The inner function is $u = \pi x$ .

The outer function is $f(u) = \tan{u}$ .

$\frac{dy}{dx} = y^{\prime} = \sec^{2}(u)*\pi = \pi\sec^{2}{\pi x}$

Step-by-step explanation:

The inner function is the one we apply the outer function to.

$y = \tan{\pi x}$

We apply the outer function tangent to $\pi x$ .

So, the inner function is $u = \pi x$ .

The outer function is $f(u) = \tan{u}$ .

The derivative of a compositve function

$y = f(u)$ in which $u = g(x)$ is given by the following function.

$y^{\prime} = f^{\prime}(u)*g^{\prime}(x)$

$f(u) = \tan{u}$

$f^{\prime}(u) = \sec^{2}{u}$

$u = g(x) = \pi x$

$g^{\prime}(x) = \pi$

$y^{\prime} = f^{\prime}(u)*g^{\prime}(x)$

$\frac{dy}{dx} = y^{\prime} = \sec^{2}(u)*\pi = \pi\sec^{2}{\pi x}$

7 0

2 years ago

Please help ASAP 25 pts + brainliest to right/best answer

zhuklara [117]

Answer:

Step-by-step explanation:

LOGb(x)=y

4^5=1024

= log(4)1024=5

4 0

3 years ago

PLEASE HELP ME!

kotegsom [21]

Answer:

Bottom left graph

Step-by-step explanation:

We have to use what is called the zero-interval test [test point] in order to figure out which portion of the graph these inequalities share:

−2x + y ≤ 4 >> Original Standard Equation

+ 2x + 2x

_________

y ≤ 2x + 4 >> Slope-Intercept Equation

−2[0] + 0 ≤ 4

0 ≤ 4 ☑ [We shade the part of the graph that CONTAINS THE ORIGIN, which is the right side.]

$\displaystyle y > x + 2 \\ \\ 0 ≯ 2$ [We shade the part of the graph that does not contain the origin, which is the left side.]

So, now that we got that all cleared up, we can tell that the graphs share a region in between each other and that they both have POSITIVE RATE OF CHANGES [SLOPES], therefore the bottom left graph matches what we want.

** By the way, you meant $\displaystyle y > x + 2$ because this inequality in each graph is a dashed line. It is ALWAYS significant that you be very cautious about which inequalities to choose when graphing. Inequalities can really trip some people up, so once again, please be very careful.

I am joyous to assist you anytime.

7 0

2 years ago

What's the following sequence

Dmitry [639]

Your answer is A !! go for it !!

8 0

2 years ago

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