The volume that will occupy at STP is calculated as follows
by use of ideal gas equation
that is PV=nRT where n is number of moles calculate number of moles
n= PV/RT
p=0.75 atm
V=6.0 L
R = 0.0821 L.atm/k.mol
T= 35 +273= 308k
n=?
n= (o.75 atm x 6.0 L)/( 0.0821 L.atm/k.mol x 308 k)= 0.178 moles
Agt STP 1 mole= 22.4 L what obout 0.178 moles
= 22.4 x0.178moles/ 1moles =3.98 L( answer C)
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Answer:
Explanation:
Step 1. Identify the Group that contains X
We look at the consecutive ionization energies and hunt for a big jump between them
We see a big jump between n = 2 and n = 3. This indicates that X has two valence electrons.
We can easily remove two electrons, but the third electron requires much more energy. That electron must be in the stable, filled, inner core.
So, X is in Group 2 and P is in Group 15.
Step 2. Identify the Compound
X can lose two valence electrons to reach a stable octet, and P can do the same by gaining three electrons.
We must have 3 X atoms for every 2 P atoms.
The formula of the compound is .
Answer:
(1) 720 seconds (2) 10800 seconds (3) 17 dozens (4) 1.45 x (5) 13.29 moles
Explanation:
(1) 720 seconds
1 minute = 60 seconds
12 minutes = 720 seconds (12 x 60)
(2) 10800 seconds
1 hour = 60 minutes 1 minute = 60 seconds
3 x 60 = 180 minutes in 3 hours
180 x 60 = 10800 seconds in 180 minutes that are in 3 hours
(3) 17 dozens
1 dozen = 12
204 ÷ 12 = 17 dozens
(4) 1.45 x
8.00 moles CO2 x = 24.0 moles atoms
24.0 moles x = 1.45 x
(5) 13.29 moles
sorry but I'm not fully sure if this one is correct
8 x x = 13.29 moles