Have a wonderful day :) thanks for the points
Answer:
K3PO4
Explanation:
Recall that colligative properties depends on the number of particles present. The greater the number of particles present, the greater the degree of colligative properties of the solution. Let us look at each option individually;
SrCr2O7-------> Sr^2+ + Cr2O7^2- ( 2 particles)
C4H11N (not ionic in nature hence it can not dissociate into ions)
K3PO4-------> 3K^+ + PO4^3- (4 particles)
Rb2CO3-------> 2Rb^+ + CO3^2- (3 particles)
Hence K3PO4 has the greatest number of particles and will display the greatest colligative effect.
2.4(10^3)
=2.4*10^3
=2.4*(10*10*10)
=2400 <span>milliliters
To </span>centiliters is<span> 2400mL= <u>240.0000cl. </u> </span>
Answer: The product from the reduction reaction is
CH3-CH2-CH(CH3)-CH2-CH2OH
IUPAC name; 3- Methylpentan-1-ol
Explanation:
Since oxidation is simply the addition of oxygen to a compound and reduction is likewise the addition of hydrogen to a compound.
Therefore, hydrogen is added onto the carbon atom adjacent to oxygen in 3- methyl pentanal
CH3 CH2 CHCH3 CH2 CHO thereby -CHO( aldehyde functional group) are reduced to CH2OH ( Primary alcohol) which gives;
3-methylpenta-1-ol .
The structure of the product is:
CH3-CH2-CH(CH3)-CH2-CH2OH