Part A: y-intercept = 12 miles
Part B: Find the average rate of change: 36 - 20/2 = 16/2 = 8 mph
This tells us that the bird can travel long distances.
Part C: 172 - 12 = 160 miles at a rate of 8 mph
160 mi ÷ 8mph = 20 hrs
Domain of function = 0 ≤ x ≤ 20
Answer:
Uche's pumping rate is <u>300 mL/s</u>.
Step-by-step explanation:
Given:
Uche pumps gasoline at a rate of 18 L/min.
Now, to find Uche's pumping rate in mL/s.
The rate at which Uche pumps gasoline = 18 L/min.
So, to get the pumping rate in mL/s we use convert L/min to mL/s by using conversion factor:
<u>1 L/min = 16.6667 mL/s.</u>
18 L/min = 16.6667 × 18 mL/s.
18L/min = 300 mL/s.
Therefore, Uche's pumping rate is 300 mL/s.
Answer:
3.5
Step-by-step explanation:
500 x 7
3500/1000
3.5
1 = sin²0 + cos²0
sin²0 = 1 - cos²0
sin²0 = 1 - 11/36
sin²0 = 25/36
sin 0 = 5/6 or -5/6
In the first quadrant, the values for sin, cos and tan are positive.
sin0 = 5/6
The answer is the second answer choice, an = -13 + 5(n - 1)