To determine the centroid, we use the equations:
x⁻ =
1/A (∫ (x dA))
y⁻ = 1/A (∫ (y dA))
First, we evaluate the value of A and dA as follows:
A = ∫dA
A = ∫ydx
A = ∫3x^2 dx
A = 3x^3 / 3 from 0 to 4
A = x^3 from 0 to 4
A = 64
We use the equations for the centroid,
x⁻ = 1/A (∫ (x dA))
x⁻ = 1/64 (∫ (x (3x^2 dx)))
x⁻ = 1/64 (∫ (3x^3 dx)
x⁻ = 1/64 (3 x^4 / 4) from 0 to 4
x⁻ = 1/64 (192) = 3
y⁻ = 1/A (∫ (y dA))
y⁻ = 1/64 (∫ (3x^2 (3x^2 dx)))
y⁻ = 1/64 (∫ (9x^4 dx)
y⁻ = 1/64 (9x^5 / 5) from 0 to 4
y⁻ = 1/64 (9216/5) = 144/5
The centroid of the curve is found at (3, 144/5).
Multiply the length and width together:
3 2 6
A = ------ * ------ = --------
5 5 25
None of the given possible answers make any sense. Please ensure that you have copied down this problem exactly as presented.
If the width were 2/5 in and the length 3/5 in, then, using decimal fractions, the area would be
A = 0.4(0.6) = 0.24 in^2, which is miles and miles away from 15 in^2 (for example)
Answer:
Oh, I done this before
Step-by-step explanation:
you have to find the least valur and put it to least to greatest!
MArk me brianliest!
On the 40th and the 80th you will receive both a free beverage and a free appetizer. You can find this by simply finding the multiples of both number up to 100 (or a little more than 100) to find out on which dates you'd get bothe an appetizer and beverage for free. Here are the multiples of both, to prove this answer.
- 8: 8, 16, 24, 32, 40, 48, 56, 64, 72, 80, 88, 96, 104.
- 10: 10, 20, 30, 40, 50, 60, 70, 80, 90, 100.
Thus making 40 and 80 the answers. I hope this helps!
Let A be college A and let B be College B
A= 14,100
Rule: 1 Year = +1,000 students
B= 34,350
Rule: -1250 per year
1st Answer: 2017
Notice: I didn't show the formula because I'm not %100 sure I'm kind of off so if this is incorrect I'm deeply sorry. I truly am. On the bright side, I think its correct.