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2 years ago

Determine if the statement is true or false 10,000-99,999<0

Mathematics

1 answer:

a_sh-v [17]2 years ago

3 0

It would be true because 10,000-99,999=-89999 -89999<0 is true

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Help me solve these step by step please !!!

Anettt [7]

Answer:

#2) is 25

Step-by-step explanation:

the best way to solve any of theses is in the order of pemdas:

●parentheses

●exponents

●multiplication & division

●addition & subtraction

for example lets do #2

9+ (2^2)(4)

the first parenthesis has exponents so you'd do it first. 2^2 (two two times) is 4

9+(4)(4)

when two parentheses are next to Each other you multiply. 4x4 is 16

9+16

then finally you add

use these steps for the rest. just comment if you have any questions

7 0

3 years ago

Read 2 more answers

5. The number −6 is 2 more than an unknown number. Find the unknown number.

Mariana [72]

Answer:

-4

Step-by-step explanation:

-6 - 2 = -4

3 0

2 years ago

A company has recently been hiring new employees. Today the company has 34% more employees than it did a year ago. If there are

Anton [14]

Answer:

22110 employees.

Step-by-step explanation:

33500 decrease 34% =

33500 × (1 - 34%) = 33500 × (1 - 0.34) = 22110

5 0

2 years ago

Read 2 more answers

Prove that the triangle EDF is isosceles. Give reasons for your answer.

Gekata [30.6K]

Answer:

$\triangle EDF$ is isosceles.

Step-by-step explanation:

Please have a look at the attached figure.

We are given the following things:

$\angle EDF = y$

$\text{External }\angle DFG = 90 +\dfrac{y}{2}$

Let us try to find out $\angle E$ and $\angle DFE$ . After that we will compare them.

Finding  $\angle DFE$ :

Side EG is a straight line so $\angle GFE = 180$

$\angle GFE$ is sum of internal $\angle DFE$ and external $\angle DFG$

$\angle GFE = 180 = \angle DFE + \angle DFG\\\Rightarrow 180 = \angle DFE + (90+\dfrac{y}{2})\\\Rightarrow \angle DFE = 180 - 90 - \dfrac{y}{2}\\\Rightarrow \angle DFE = 90 - \dfrac{y}{2} ....... (1)$

Finding  $\angle E$ :

Property of external angle: External angle in a triangle is equal to the sum of two opposite internal angles of a triangle.

i.e. external $\angle DFG$ = $\angle E + \angle EDF$

$\Rightarrow 90+\dfrac{y}{2} = \angle E + y\\\Rightarrow \angle E = 90+\dfrac{y}{2} -y\\\Rightarrow \angle E = 90-\dfrac{y}{2} ....... (2)$

Comparing equations (1) and (2):

It can be clearly seen that:

$\angle DFE = \angle E =90-\dfrac{y}{2}$

The two angles of $\triangle EDF$ are equal hence $\triangle EDF$ is isosceles.

8 0

2 years ago

Answer? please help :))

gtnhenbr [62]

Answer:

(0,1)(4,9)

Step-by-step explanation:

8 0

2 years ago