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2 years ago

When grip strength increases:

Physics

1 answer:

Nitella [24]2 years ago

5 0

Answer:

e. the number of active motor units increases.

Explanation:

There is a direct relationship between the number of active motor units and the grip strength in a given scenario. <em>For example, increase in the grip strength leads to increase in the number of active motor units. In the other-hand, the decrease in grip strength leads to the decrease in the number of active motor units.</em>

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If you add air to a flat tire through a single small entry hole, why does the air spread out to fill the tire

Natali [406]

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2 years ago

Read 2 more answers

A series RLC circuit has a resistance of 57.61 W, a capacitance of 13.13 mF, and an inductance of 196.03 mH. The circuit is conn

Firdavs [7]

Answer:

voltage across = 1.6 V

Explanation:

given data

resistance R = 57.61 Ω

capacitance c = 13.13 mF = 13.13 × $10^{-3}$ F

inductance L = 196.03 mH = 0.19603 H

fixed rms output Vrms = 23.86 V

to find out

voltage across circuit

solution

we know resonant frequency that is

resonant frequency = 1 / ( 2π√(LC)

put the value

resonant frequency = 1 / ( 2π√(0.19603×13.13 × $10^{-3}$ )

resonant frequency f = 3.1370 HZ

so current will be at this resonant is

current = Vrms / R

current = 23.86 / 57.61

current = 0.4141 A

and

so voltage across will be

voltage across = current / ( 2π f C )

voltage across = 0.4141 / ( 2π ( 3.1370) 13.13 × $10^{-3}$ )

voltage across = 1.6 V

4 0

2 years ago

A dog pulls on a leash with a force of 15 23 is a big dog. The leash makes an angle of 36.7 degrees to the horizontal. What are

ch4aika [34]

Answer:

$x = 12.027N$ and $y = 8.964N$

Explanation:

The first sentence of this question is not explanatory enough. However, I'll assume the force to be 15N

$Force = 15N$

$\theta = 36.7$ to the horizontal

Required

Solve for the x and y components

Since the given angle is to the horizontal, the x and y coordinates are calculated using the following illustrations.

$Sin\theta = \frac{y}{Force}$ ---- y component

$Cos\theta = \frac{x}{Force}$ ---- x component

Calculating the y component.

Substitute 15 for Force and 36.7 for $\theta$

$Sin\theta = \frac{y}{Force}$ becomes

$Sin(36.7) = \frac{y}{15}$

Make y the subject

$y = 15 * Sin(36.7)$

$y = 15 * 0.5976$

$y = 8.964N$

Calculating the x component.

Substitute 15 for Force and 36.7 for $\theta$

$Cos\theta = \frac{x}{Force}$ becomes

$Cos(36.7) = \frac{x}{15}$

Make y the subject

$x = 15 * Cos(36.7)$

$x = 15 * 0.8018$

$x = 12.027N$

<em>Hence, the x and y components of the force are: 8.964N and 12.027N respectively.</em>

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2 years ago

1:a boy 2 a girl pulling a heavy crate at the same time w/10 unite of force each.What is the net force acting on the object

vovangra [49]

The maximum magnitude of the net force on the box is 20 N, which is only possible if the boy and the girl pull the box together in the same direction, horizontally and parallel to the ground.
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2 years ago

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Afina-wow [57]

Answer:

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Explanation:

I hope this helped

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2 years ago