(36 3/4" + 36 3/8" + 371/2" +z) /4 = 36 5/8"
This is the equation that you would get for the average. Now we just solve for z.
Following PEMDAS you have to mulitply the equation by 4 to get rid of the divide by 4 part.
4( (36 3/4" + 36 3/8" + 371/2" +z) /4 = 36 5/8)
Which does this
36 3/4" + 36 3/8" + 371/2" +z = 146 1/2"
Now you have to add and subtract to get "z" by itself.
36 3/4" + 36 3/8" + 371/2" = 110 5/8"
(110 5/8" + z = 146 1/2" ) -110 5/8"
z= 35 7/8", so the answer is b
Look like whatever <span>3.5×2</span> is. (7)
Answer:
Step-by-step explanation:
Complete Question:
Chapter 6, Section 1-D, Exercise 009 Is a Normal Distribution Appropriate? In each case below, is the sample size large enough so that the sample proportions follow a normal distribution?
a) n=600 p=0.2
b) n=20, p=0.4
if np=10 and npq=10 then the data follows normal distribution
a) np= 120,
q= 1-0.2= 0.8
npq= 600 ×0.2×0.4 = 48
Normal distribution is appropriate and sample size is large enough
b) np= 8
q= 1-0.4= 0.6
npq= 20 × 0.4×0.6= 4.8
sample size is not large enough so normal distribution is not appropriate.
a. Use the inclusion/exclusion principle.
b. By definition of conditional probability,
I think it is -2, if that helps
