All categories

2 years ago

PLS HELP ASAP IT DETECT IF ITS Right OR WRONG HELPP

Mathematics

1 answer:

Lilit [14]2 years ago

3 0

Answer:

the answer i believe is right angles

You might be interested in

HELPPPPP!!! Can you TEACH ME HOW TO DO THIS and will give b

IRINA_888 [86]

Answer:

yh I can help the answer is 185/1000 bc u have to convert it as a fraction and u can simplify it by 5 then the answer will be 37/200 plz try this if not I will tell u something else

5 0

2 years ago

Simplify 8 over the quantity of 2 plus 2i

Sergeu [11.5K]

Answer should be: 2 + 2i

8 0

2 years ago

Read 2 more answers

A tourist calculated that if he walks to the railroad station with a speed of 4 mph, he’ll miss the train by half an hour, but

nevsk [136]

You have to do speed over time to find out the distance the tourist will have to cover. (Speed multiplied by time= distance)

7 0

2 years ago

8(5-32) equal to and explain please help

Gre4nikov [31]

You would use order of operations: PEMDAS
P(parenthesis) E(exponents) MD(multiplication/division) AS(addition/subtraction)
with MD and AS order doesnt matter.
8(5-32) you would start with inside the Parenthesis for "P" so (5-32)=(-27)
next you would go to the E but because you dont have an exponent you go to the next step with is the "MD" you have multiplication so next would be 8(-27) and 8 multiplied by -27 is: 8(-27)= -216
ANSWER: -216

4 0

2 years ago

Read 2 more answers

A small lawnmower company produced 1,500 lawnmowers in 2008. In an effort to determine how maintenance-free these units were, th

ikadub [295]

Answer:

The 95% confidence interval for the average number of years until the first major repair is (3.1, 3.5).

Step-by-step explanation:

The (1 - α)% confidence interval for the average using the finite correction factor is:

$CI=\bar x\pm z_{\alpha/2}\cdot\frac{\sigma}{\sqrt{n}}\cdot\sqrt{\frac{N-n}{N-1}}$

The information provided is:

$N=1500\\n=183\\\sigma=1.47\\\bar x=3.3$

The critical value of z for 95% confidence level is,

z = 1.96

Compute the 95% confidence interval for the average number of years until the first major repair as follows:

$CI=\bar x\pm z_{\alpha/2}\cdot\frac{\sigma}{\sqrt{n}}\cdot\sqrt{\frac{N-n}{N-1}}$

$=3.3\pm 1.96\times\frac{1.47}{\sqrt{183}}\times\sqrt{\frac{1500-183}{1500-1}}\\\\=3.3\pm 0.19964\\\\=(3.10036, 3.49964)\\\\\approx (3.1, 3.5)$

Thus, the 95% confidence interval for the average number of years until the first major repair is (3.1, 3.5).

7 0

2 years ago