We don't need the figure
angle b = 44 degrees
angle a = 62 degrees
angle e = 50 degrees
angle f = unknown
we know that
angle a + b + e + f = 180 degrees
50 + 44 + 62 + f =180 degrees
f= 180-50-44-62
but here there is only one blank so we have to add 44 and 62 to make one number that is 106
therefore, f = 180-50-106
if you further want to solve it angle f is 24
Answer:
Step-by-step explanation:
The rectangular prism has a volume equal to V=xyz. V=(1/3)3(5/3)=5/3 in^3. The cube has a volume equal to V=s^3. The volume of the cube is equal to the prism when
<span>The Volume of a Cylinder = </span><span>π <span>• r² • height<span>
</span></span></span>radius = 13.5 feet
volume = PI * 13.5^2 * 4 feet (the problem states it is to be filled to a depth of 4 feet)
volume = PI * 182.25 * 4
volume =
<span>
<span>
<span>
2,290 cubic feet</span></span></span>
The hose delivers 80 <span>cubic feet per hour so it will take:
</span>2,290 / 80 =
<span>
<span>
<span>
28.625
</span>
</span>
</span>
hours
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The volume of the pool is:
volume = PI * 182.25 * 4.5
=
<span>
<span>
<span>
2,576.</span></span></span>5 cubic feet
Answer:
where is the spinner
Step-by-step explanation:
Answer:
x = 2
Step-by-step explanation:
These equations are solved easily using a graphing calculator. The attachment shows the one solution is x=2.
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<h3>Squaring</h3>
The usual way to solve these algebraically is to isolate radicals and square the equation until the radicals go away. Then solve the resulting polynomial. Here, that results in a quadratic with two solutions. One of those is extraneous, as is often the case when this solution method is used.
The solutions to this equation are the values of x that make the factors zero: x=2 and x=-1. When we check these in the original equation, we find that x=-1 does not work. It is an extraneous solution.
x = -1: √(-1+2) +1 = √(3(-1)+3) ⇒ 1+1 = 0 . . . . not true
x = 2: √(2+2) +1 = √(3(2) +3) ⇒ 2 +1 = 3 . . . . true . . . x = 2 is the solution
__
<h3>Substitution</h3>
Another way to solve this is using substitution for one of the radicals. We choose ...
Solutions to this equation are ...
u = 2, u = -1 . . . . . . the above restriction on u mean u=-1 is not a solution
The value of x is ...
x = u² -2 = 2² -2
x = 2 . . . . the solution to the equation
_____
<em>Additional comment</em>
Using substitution may be a little more work, as you have to solve for x in terms of the substituted variable. It still requires two squarings: one to find the value of x in terms of u, and another to eliminate the remaining radical. The advantage seems to be that the extraneous solution is made more obvious by the restriction on the value of u.