Solution:- Given numbers to compare are 512 and 521 .
As they are 3 digit numbers
So, we have to compare hundreds place.
But hundreds are equal in both the numbers with digit 5.
Next we have to compare tens place.
Case 1 :- 1 ten is smaller in 512 than 2 tens in 521 .
So we get the result that,
512 is smaller than 521
or <em> 512 < 521</em>
Case 2:-2 tens is greater in 521 than 1 ten in 512 .
So we get the result that,
521 is greater than 512
or <em> 521 > 512</em>
Answer:
p^2 + q^2 = 22/9.
Step-by-step explanation:
For a quadratic function ax^2 + bx + c if the zeroes are A and B then
A + B = -b/a and AB = c/a.
2x^2 - 7x + 3
Now p and q are the zeroes of the above function so
p + q = 7/3 and pq = 3/2.
Now p^2 + q^2 = (p + q)^2 - 2pq
= (7/3)^2 - 2* 3/2
= 49/9 - 3
= 49/4 - 27/9
= 22/9.
Answer:
19
Step-by-step explanation:
PEMDAS
no parenthesis
no exponents
4-6+2 x 7
4-6+ 17
no division
4-6=2
2+17
19 is the answer
1. $1.23 per pair
A dozen is 12 so you do 12x7=84
Then you do 103.32 divided by 84 which gives you 1.23
2. His error was doing 103.32 divided by 7 because he thought it was only 7 pairs but it’s 7 dozen.
Step-by-step explanation:
$800 × 5% = $40
for 1 year, I earn $40
100 ÷ 40 = 2 remainder 2
Therefore I would have to leave the money in for at least 3 years to earn $100