Hmm
what you do is try to eliminate 1 variable in 2 equaions first
we can elminate x's in first and 2nd equation
add first and 2nd equation
x+3y-2z=10
<u>-x-2y+z=-7 +</u>
0x+y-z=3
y-z=3
multiply 2nd equation by 3 and add to last one
-3x-6y+3z=-21
<u>3x+9y-5z=28 +</u>
0x+3y-2z=7
3y-2z=7
we now have
y-z=3
3y-2z=7
multiply first equation by -2 and add to 2nd
-2y+2z=-6
<u>3y-2z=7 +</u>
y+0z=1
y=1
now we can sub back
y-z=3
1-z=3
minus 1
-z=2
times -1
z=-2
sub baack into any equation
x+3(1)-2(-2)=10
x+3+4=10
x+7=10
minus 7
x=3
x=3
y=1
z=-2
(3,1,-2)
Answer is D
Please mark me as brainless if right
Answer:
0, -2, 2, -1
Step-by-step explanation:
You are trying to make it so that the one of the ( )= 0.
An example is (x+15) or (2x+3)
the first l one would be x= -15 since -15+15 would equal 0.
The second one is -3/2 since it would be -3+3 which would equal 0.
also since the equation starts with x( or -x it doesn't really matter) one of the zeros would also be 0.
Hope this helps!
Answer:
C. X = 10.247
Step-by-step explanation:
X -4.21 = 6.047
just you will add 4.21 to both sides of the equation
X -4.21 + 4.21 = 6.047 + 4.21
X = 10.247
