Lay her on the scale that would work
Assuming Hardy-Weinberg equilbrium, we have
p + q = 1
where p = frequency of dominant allele and q = frequency of recessive allele. So
p = 1 - q = 1 - 0.04 = 0.96
Consequently we have
• p² = 0.9216 = frequency of hom ozygous domininant genotype
• pq = 0.0768 = frequency of heterozygous genotype
• q² = 0.0016 = frequency of hom ozygous recessive genotype
since
p² + 2pq + q² = 1
Answer: THEY ARE INVOLVED IN THE DISASSEMBLY OF THE NUCLEAR ENVELOPE
Explanation: The disassembly of the nuclear envelope is triggered by the cyclin‐dependent kinase at the onset of mitosis. At this point, Integral nuclear membrane proteins diffuse/move into the endoplasmic reticulum (ER) after nuclear envelope breakdown. The nuclear envelope reassembles around compact chromosome mass at late anaphase/telophase and the chromosomes condenses and become visible.
