2 years ago

HELP ASAP PLEASEEE!!

Mathematics

1 answer:

stepan [7]2 years ago

8 0

What’s the question i cant see it??

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Need help its sector area

Paladinen [302]

Area of sector

$= \frac{30}{360} \times \pi \times {(radius)}^{2}$

$= \frac{30}{360} \times \ \frac{22}{7} \times {(12)}^{2}$

$= \frac{30}{360} \times \ \frac{22}{7} \times 12 \times 12$

so the area = 37.71 square metre

8 0

2 years ago

Can you prove this congruent? Using what theorem/postulate?

slavikrds [6]

I'd say that, if the angles S and U are equal, as the SV and UV segments move towards each other, they meet at vertex V, the angles they make, angle SVT and UVT, have to be equal, because the side TV is shared by both, and has the same direction.

now, side TV is on both triangles, and is shared by both, so is the same length, so TV on one triangle is equal to TV on the other

check the picture below

so, you have one Angle, another Angle, and then a Side
A A S