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2 years ago

A fish tank contains 24 L of water. Water is added to increase the volume by 12.5%. What is the new volume of water in the tank?

Mathematics

1 answer:

Ronch [10]2 years ago

6 0

Answer:

27 L

Step-by-step explanation:

To find 12.5% of 24, move the decimal all the way to the left and multiply 24 by 0.125. You get 3, which is how much was added to the original volume.

24 + 3 = 27, which is the new volume.

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Select all the correct answers Which functions are the same as their inverse functions?

KIM [24]

Answer:

f(x)

Step-by-step explanation:

f(x)=x-1/x+5

y=x-1/x+5

xy+5y=x-1

xy-x=-1-5y

x(y-1)=1-5y

x=-1-5y/y-1

x=-5

6 0

2 years ago

find the area of the trapezium whose parallel sides are 25 cm and 13 cm The Other sides of a Trapezium are 15 cm and 15 CM

Snezhnost [94]

$\huge\underline{\red{A}\blue{n}\pink{s}\purple{w}\orange{e}\green{r} -}$

Given - A trapezium ABCD with non parallel sides of measure 15 cm each ! along , the parallel sides are of measure 13 cm and 25 cm

To find - Area of trapezium

Refer the figure attached ~

In the given figure ,

AB = 25 cm

BC = AD = 15 cm

CD = 13 cm

Construction -

$draw \: CE \: \parallel \: AD \: \\ and \: CD \: \perp \: AE$

Now , we can clearly see that AECD is a parallelogram !

$\therefore$ AE = CD = 13 cm

Now ,

$AB = AE + BE \\\implies \: BE =AB - AE \\ \implies \: BE = 25 - 13 \\ \implies \: BE = 12 \: cm$

Now , In ∆ BCE ,

$semi \: perimeter \: (s) = \frac{15 + 15 + 12}{2} \\ \\ \implies \: s = \frac{42}{2} = 21 \: cm$

Now , by Heron's formula

$area \: of \: \triangle \: BCE = \sqrt{s(s - a)(s - b)(s - c)} \\ \implies \sqrt{21(21 - 15)(21 - 15)(21 - 12)} \\ \implies \: 21 \times 6 \times 6 \times 9 \\ \implies \: 12 \sqrt{21} \: cm {}^{2}$

Also ,

$area \: of \: \triangle \: = \frac{1}{2} \times base \times height \\ \\\implies 18 \sqrt{21} = \: \frac{1}{\cancel2} \times \cancel12 \times height \\ \\ \implies \: 18 \sqrt{21} = 6 \times height \\ \\ \implies \: height = \frac{\cancel{18} \sqrt{21} }{ \cancel 6} \\ \\ \implies \: height = 3 \sqrt{21} \: cm {}^{2}$

Since we've obtained the height now , we can easily find out the area of trapezium !

$Area \: of \: trapezium = \frac{1}{2} \times(sum \: of \:parallel \: sides) \times height \\ \\ \implies \: \frac{1}{2} \times (25 + 13) \times 3 \sqrt{21} \\ \\ \implies \: \frac{1}{\cancel2} \times \cancel{38 }\times 3 \sqrt{21} \\ \\ \implies \: 19 \times 3 \sqrt{21} \: cm {}^{2} \\ \\ \implies \: 57 \sqrt{21} \: cm {}^{2}$

hope helpful :D

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1 year ago

Fill in the blank (no word bank)

timofeeve [1]

Answer:

Alternate Interior Angles:

∠3 ≅ ∠5

Corresponding Angles:

∠3 ≅ ∠7

∠4 ≅ ∠8

Supplementary Angles:

∠3 is supplementary to ∠6

Step-by-step explanation:

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2 years ago

Perform the indicated operation -3+14= ?

Zigmanuir [339]

The answer is -3+14=11

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2 years ago

Find the l.c.m of x²+x, x²-1, x²-x

olga2289 [7]

Answer:

X³-x

Step-by-step explanation:

Lcm

x(x-1)(x+1)

x(x²-1)

x³-x

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1 year ago